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Windows 环境下设备驱动程序设计,很好的资料,拿来共享
Windows 环境下设备驱动程序设计,很好的资料,拿来共享-Windows environment, device driver design, very good information, brought to share
- 2022-05-18 02:40:16下载
- 积分:1
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这是一个模拟时钟的原代码
这是一个模拟时钟的原代码-This is a simulation of the original code Clock
- 2022-01-26 00:54:15下载
- 积分:1
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把两个数组合并,并查询
把两个数组合并,并查询-merging the two arrays, and inquiries
- 2023-01-12 22:30:03下载
- 积分:1
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一个delphi7做的双色球随机选号,模拟摇奖程序
一个delphi7做的双色球随机选号,模拟摇奖程序-Loans delphi7 do a random选号, Analog摇奖procedures
- 2022-03-23 00:15:03下载
- 积分:1
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主要介绍在SuperMap IS .NET的使用和开发过程中需要了解和掌握的一些专题内容,包括许可配置信息、数字水印功能、智能集群缓存...
主要介绍在SuperMap IS .NET的使用和开发过程中需要了解和掌握的一些专题内容,包括许可配置信息、数字水印功能、智能集群缓存-Mainly describes the SuperMap IS. NET s use and development process need to understand and master a number of topics, including the license configuration information, digital watermarking capabilities, intelligent clustered cache
- 2022-11-10 16:15:03下载
- 积分:1
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C语言精彩编程百例5
C语言精彩编程百例5-C programming language brilliant five hundred cases
- 2022-02-04 20:47:10下载
- 积分:1
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一元多项式的加法代码欢迎大家支持,我也需要你们的帮助,我们大家共同进步。...
一元多项式的加法代码欢迎大家支持,我也需要你们的帮助,我们大家共同进步。-One of the additive polynomial code welcomes U.S. support, I also need your help, we all progress together.
- 2022-05-05 19:41:19下载
- 积分:1
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算法分析与设计中的经典问题,利用回溯法解决背包问题,有详细的代码段。...
算法分析与设计中的经典问题,利用回溯法解决背包问题,有详细的代码段。-Algorithm analysis and design of the classic problems, the use of backtracking to solve knapsack problem, there is a detailed code snippet.
- 2022-02-03 18:03:27下载
- 积分:1
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输入一个句子(由空格分隔的若干个词)将该句子按如下的要求输出:
1.第偶数个词反序,第奇数个词不反序
2.个词之间只留一个空格
3.句首和句尾不留空...
输入一个句子(由空格分隔的若干个词)将该句子按如下的要求输出:
1.第偶数个词反序,第奇数个词不反序
2.个词之间只留一个空格
3.句首和句尾不留空格-importation of a sentence (space separated by the number of words) Revise the sentence requested by the following output : 1. even the first-term anti-sequence, section 000 odd word does not fight sequence two. between the words out, leaving only a blank 3. the first sentence and the end of the sentence without leaving spaces
- 2022-02-09 18:33:21下载
- 积分:1
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一个简易日历程序,已知公元元年一月一日即耶稣诞生日是星期一,那么因为365%7=1,366%7=2。所以每过一年平年星期数加一,每过一年闰年星期数加二,依次类推...
一个简易日历程序,已知公元元年一月一日即耶稣诞生日是星期一,那么因为365%7=1,366%7=2。所以每过一年平年星期数加一,每过一年闰年星期数加二,依次类推就可以求出任意一年一月一日是星期几。-a simple calendar program, known Year on January 1 that the first year of the birth of Jesus Day is Monday, because 365% = 1,366 7% 7 = 2. So every non-leap year over year increase in a few weeks, a leap year every year the number increases two weeks, followed by analogy can be found arbitrary January 1, 2001 is several weeks.
- 2022-02-04 23:46:52下载
- 积分:1