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VC++实现GPS全球定位系统定位数据的提取,串口技术的应用
VC++实现GPS全球定位系统定位数据的提取,串口技术的应用-VC GPS positioning data extraction, serial technology applications
- 2022-03-15 14:57:17下载
- 积分：1
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扫描线算法中的一种,在vb下运行,比较好用
扫描线算法中的一种,在vb下运行,比较好用-scan lines of an algorithm, vb running, the better quality
- 2023-02-25 05:25:03下载
- 积分：1
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ghost软件
一款很好用的备分工具
绝对好用
ghost软件
一款很好用的备分工具
绝对好用-A good software ghost of a breakdown definitely handy tool
- 2022-09-30 00:50:19下载
- 积分：1
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在开发板TMS320C5402下调试灯闪的程序
在开发板TMS320C5402下调试灯闪的程序-the TMS320C5402 Development Board under the lights blinking debugging procedures
- 2022-07-07 09:08:09下载
- 积分：1
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Overview DSN
Overview DSN-Less Connection dBASE Excel Text File Visual FoxPro Access database SQL Server Oracle MySQL AS400 Sybase Sybase SQL AnyWhere DSN Connection -Overview DSN-Less Connection dBASE Excel Text File Access Visual FoxPro database SQL Ser ver Oracle MySQL Front Sybase Sybase SQL AnyWhe "re DSN Connection
- 2023-07-13 12:45:02下载
- 积分：1
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解决以下问题：
For solving the following problem:
"There is No Free Lunch"
Time Limit: 1 Second Memory Limit: 32768 KB
One day, CYJJ found an interesting piece of commercial from newspaper: the Cyber-restaurant was offering a kind of "Lunch Special" which was said that one could "buy one get two for free". That is, if you buy one of the dishes on their menu, denoted by di with price pi , you may get the two neighboring dishes di-1 and di+1 for free! If you pick up d1, then you may get d2 and the last one dn for free, and if you choose the last one dn, you may get dn-1 and d1 for free.
However, after investigation CYJJ realized that there was no free lunch at all. The price pi of the i-th dish was actually calculated by adding up twice the cost ci of the dish and half of the costs of the two "free" dishes. Now given all the prices on the menu, you are asked to help CYJJ find the cost of each of the dishes.
- 2022-12-06 21:00:03下载
- 积分：1
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同济大学的 陈以一教授的《钢结构基本原理》第3章
同济大学的 陈以一教授的《钢结构基本原理》第3章
- 2022-03-31 13:32:38下载
- 积分：1
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DSP的一个实验程序，通过该程序可以实现对DSP运行的掌握，还可以熟悉CCS的用法。...
DSP的一个实验程序，通过该程序可以实现对DSP运行的掌握，还可以熟悉CCS的用法。-a DSP experimental procedure, the procedure can be achieved on the master DSP operations, but also familiar with the use of CCS.
- 2023-08-08 08:20:03下载
- 积分：1
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简单的模拟DNA配对的程序，适合初学者，使用c++编写
简单的模拟DNA配对的程序，适合初学者，使用c++编写-Simulation of simple DNA matching procedures, suitable for beginners, using c++ to prepare
- 2022-01-28 12:19:08下载
- 积分：1
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The memory game ,very amusing
记忆游戏，很好玩
- 2022-03-28 23:16:01下载
- 积分：1
