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直流电机编码器
说明: stm32直流电机电机编码器 定时器编码器模式(timer encoder mode........)
- 2020-06-19 06:40:02下载
- 积分:1
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ArcObject
说明: 一本介绍ArcObject组件开发的书,介绍GIS二次开发(Copies of the book ArcObject component development, secondary development of GIS introduction)
- 2010-04-13 14:31:45下载
- 积分:1
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shortest-path
通信网络的架设问题 若要在n(≥10)个城市之间建设通信网络,只需要架设n-1条线路即可(With the Dijksra algorithm to network G from source points to the rest of the vertices of the shortest path)
- 2014-01-11 23:32:27下载
- 积分:1
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ARM_FGA_DEV
采用LPC的芯片做的气体排放检测,包括气体成分分析,数据的处理,数据传输给工作站.(LPC chips used to do the detection of gas emissions, including gas composition analysis, data processing, data transmission to the workstation.)
- 2008-08-05 20:14:20下载
- 积分:1
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5、译码器实验
基于51单片机的译码器实验,常见问题:
1. 按下按键无效果
确保连线正确
换根杜邦线试试
将单片机拆下来重新安装下,重启开发板(Decoder Experiment Based on 51 Single Chip Microcomputer, Common Problems:
1. Pressing the key has no effect
Make sure the connection is correct
Try changing the dobang line
Remove the microcontroller and reinstall it. Restart the development board.)
- 2020-06-20 17:20:02下载
- 积分:1
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msp430无刷电机PWM 及12864液晶驱动程序。CCS
包含24L01收发,12864液晶 矩阵键盘检测程序,控制PWM占空比控制电调调节电机转速。分为接收器和主机,在程序里修改宏定义就可以了。去年暑假没事写的。
- 2022-05-25 09:49:44下载
- 积分:1
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muav
地震资料倾角滤波程序,能够用于地震资料的面波去除及频谱分析(FK filter in seismic data)
- 2013-09-06 07:56:07下载
- 积分:1
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一个简单的八数码问题,你可以通过输入1到9的样字,通过训练,可以识别1到9的数字...
一个简单的八数码问题,你可以通过输入1到9的样字,通过训练,可以识别1到9的数字-A easy eight-number question,we can exercise the figure form one to nine,and the program can give out the result.
- 2023-05-17 00:00:03下载
- 积分:1
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Electronic-cipher-lock
实现一基于单片机的电子密码锁的设计,电子密码锁的设计主要由三部分组成:矩阵键盘接口电路、密码锁的控制电路、最小系统。另外系统还有LED提示灯,报警蜂鸣器等。(Realization of a microcontroller based electronic password lock design, the design of electronic password lock consists of three parts: matrix keyboard interface circuit, password lock control circuit, the minimum system. In addition, the system also has LED tips, alarm buzzer, etc..)
- 2016-11-08 15:51:11下载
- 积分:1
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c#用鼠标画直线
应用背景实现动态画图,及拖动鼠标就能动态产生图形,并且颜色是可调节的,当你不喜欢颜色时候,你可以换不同的颜色,画直线,所以这个程序很好的实现了c#的动态画图, 此程序是我自己编的,不足之处还望大家指正,谢谢大家,我们一起学习,一起进步,喜欢编程的朋友可以经常交流一下,关键技术 public partial class Form1 : Form
{
Point startPoint = new Point();
// bool showPaint = false;
public Form1()
{
InitializeComponent();
}
private void Form1_MouseDown(object sender, MouseEventArgs e)
{
startPoint = new Point(e.X, e.Y);
//{ showPaint = true; }
}
private void
- 2022-02-10 06:50:04下载
- 积分:1