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从这个源码是转载于其他网站,希望对大家有所帮助
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- 积分:1
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LCD1602驱动程序,还可以显示时间。
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- 2022-07-04 01:24:40下载
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水土保持工程概算定额》(水利部水总{2003}67号).xls
水土保持工程概算定额》(水利部水总{2003}67号).xls-fixed budget for the Soil and Water Conservation Project "(Ministry of Water total (2003) 67). Xls
- 2022-11-19 18:00:08下载
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[综合类]右击鼠标弹出菜单
[综合类]右击鼠标弹出菜单-[Comprehensive] right-click pop-up menu
- 2022-03-04 23:32:49下载
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assigning math homework with JSP service under netbeans 5.0
assigning math homework with JSP service under netbeans 5.0 -assigning math homework with JSP service under netbeans 5.0
- 2022-11-08 03:40:02下载
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算法实现题 最长公共子序列问题
给定两个序列
X = { x1 , x2 , ... , xm }
Y = { y1 , y2 , ... , yn...
算法实现题 最长公共子序列问题
给定两个序列
X = { x1 , x2 , ... , xm }
Y = { y1 , y2 , ... , yn }
求X和Y的一个最长公共子序列
举例
X = { a , b , c , b , d , a , b }
Y = { b , d , c , a , b , a }
最长公共子序列为
LSC = { b , c , b , a }-Algorithm to achieve the longest common sub-title sequence of the problem given two sequences X = (x1, x2, ..., xm) Y = (y1, y2, ..., yn) for X and Y, a maximum common substructure sequence, for example X = (a, b, c, b, d, a, b) Y = (b, d, c, a, b, a) the longest common sub-sequence for LSC = (b, c, b, a )
- 2022-03-02 12:22:07下载
- 积分:1
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单片机工具,在单片机的设计中有很大的用处,大家下载!
微控器工具,在MCU设计中大有使用,尽情下载!-Microcontroller tools, in the MCU design much use, you download!
- 2023-07-29 10:30:04下载
- 积分:1
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This is what I have compiled GDAL1.4 all documents, including dynamic library fi...
这是我已经编译好的GDAL1.4的所有文件,包括动态库文件,静态库文件,头文件。-This is what I have compiled GDAL1.4 all documents, including dynamic library files, static library files, header files.
- 2022-05-21 05:03:10下载
- 积分:1
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Single round robin tournament players winning sequence to solve the problem name...
单循环赛中选手胜负序列求解问题
名称:单循环赛中选手胜负序列求解问题
内容:有n个选手 P 1 ,P 2 ,P 3 ,… ,P n 参加了的单循环赛,每对选手之间非胜即负。现要求求出一个选手序列 P 1 ,P 2 ,P 3 ,… ,P n , 使其满足 P i 胜 P i+ 1 (i=1,… ,n-1) 。
-Single round robin tournament players winning sequence to solve the problem name: the outcome of single round-robin tournament players to solve the problem sequence elements: There are n-player P 1, P 2, P 3, ..., P n participated in a single round-robin between each pair of players Non-win or negative. Players are now required to find a sequence of P 1 " , P 2" , P 3 " , ..., P n" , to meet the P i " W P i+ 1" (i = 1, ..., n-1).
- 2022-04-01 08:15:51下载
- 积分:1
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实现文件的FTP协议上传及下载,VC++实现,测试可以运行
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- 2023-05-31 02:30:03下载
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