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好好的 好好的 好好的 好好的 好好的 好好的 好好的
好好的 好好的 好好的 好好的 好好的 好好的 好好的-Good good good good good good good good good good good good good
- 2022-10-27 17:40:03下载
- 积分:1
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10K 0.05 5MHz的频率测量误差。用ATMEGA16实现
10K到5MHz的频率测量,误差在0.05 之内。用ATmega16实现-10K to 5MHz frequency measurement error of 0.05 . Implementation with ATmega16
- 2023-04-11 12:15:03下载
- 积分:1
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连连看游戏源代码 ,本程序由visual c++编译通过,益智类小游戏.
连连看游戏源代码 ,本程序由visual c++编译通过,益智类小游戏.-Lianliankan game source code, the procedures adopted visual c compiler, knowledge-like game.
- 2022-04-01 15:00:38下载
- 积分:1
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用PSCAD做的三电平svpwm,对学电力电子和风力发电的人应该有用。...
用PSCAD做的三电平svpwm,对学电力电子和风力发电的人应该有用。-svpwm
- 2022-07-10 22:27:01下载
- 积分:1
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实现求解二次方程的程序,需先输入正确密码
实现求解二次方程的程序,需先输入正确密码-The realization of the procedure for solving quadratic equations, need to first enter the correct password
- 2023-01-22 17:40:04下载
- 积分:1
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useful to look at the
c9百例有用的来-useful to look at the
- 2022-08-23 15:37:43下载
- 积分:1
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一只赛车游戏的源始码, Visual C++ 6.0或以上适用
一只赛车游戏的源始码, Visual C++ 6.0或以上适用-a racing game Source Beginning code, Visual C 6.0 or above application
- 2023-01-30 18:25:04下载
- 积分:1
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a C workload of the teachers do Calculation Software
一个用C做的教师工作量计算软件-a C workload of the teachers do Calculation Software
- 2022-03-12 03:30:53下载
- 积分:1
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一个软件工程的软件质量web跟踪管理系统,类似于bugzilla,c#编成,sqlserver数据库...
一个软件工程的软件质量web跟踪管理系统,类似于bugzilla,c#编成,sqlserver数据库-A software engineering, web tracking software quality management system, similar to bugzilla, c# Compiled, sqlserver database
- 2023-03-08 23:30:03下载
- 积分:1
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Find prime numbers prepared by screening the function: void sieve (bool isPrime...
编写筛选查找素数函数:
void sieve(bool isPrime[], int n)
其中isPrime[ ]为一个布尔型数组,n为数组大小。由于2是第一个素数,
所以设置isPrime[0]和isPrime[1]的值为false,并设置其余的元素初值为true。
然后对从4到n-1的每一个i,判断i是否能够被2整除,如果i能够被2整除,则设置isPrime[i]为false。
对从2到n/2的每一个可能的数值重复以上处理,当操作结束时,所有值为true的isPrime[i]所对应的i就是素数,它们将是从筛子中掉下来的。-Find prime numbers prepared by screening the function: void sieve (bool isPrime [], int n) which isPrime [] as a Boolean array, n is the size of the array. Because 2 is the first prime number, so set the isPrime [0], and isPrime [1] a value of false, and set the initial value of the remaining elements of true. And then from 4 to n-1 for each i, to determine whether i can be divisible by 2, if i can be divisible by 2, then set the isPrime [i] is false. From 2 to n/2 possible values for each one to repeat the above processing, when the operation ended, all the true value of the isPrime [i] corresponding to i is a prime number, they will be falling from the sieve in the past.
- 2023-03-02 04:45:03下载
- 积分:1