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How to use InternetStatus.dll get the internet stautus? use the code as list in...
How to use InternetStatus.dll get the internet stautus? use the code as list in the Delphi Application code editing region
- 2022-02-02 16:17:21下载
- 积分：1
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UNIX模拟系统模拟得很完善！
UNIX模拟系统模拟得很完善！-写的很好 !
- 2022-01-25 15:09:14下载
- 积分：1
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问题描述:
一杯沸水冷却，圆柱体模型，底面半径0.05m，高0.1m，周围温度20度，初始水温100度
方程是四维输运方程（常数a^2=k/(c*...
问题描述:
一杯沸水冷却，圆柱体模型，底面半径0.05m，高0.1m，周围温度20度，初始水温100度
方程是四维输运方程（常数a^2=k/(c*p)，k是热传导系数0.6006焦/（米*秒*度））
初始条件：t=0时水等于100度
边界条件：1.上下壁都是自由冷却，第三类边界条件，周围温度保持在20度（H=k/h,h取1）
2.杯壁绝热，第二类边界条件
图形显示格式,取过圆柱轴的截面温度变化将其做成动画.
-Problem description : a cup of boiling water cooling cylinder model, the bottom radius of 0.05m, 0.1m high. temperature around 20 degrees, initial temperature of 100 degrees equation is four-dimensional equations (a constant ^ 2 = k/(c* p), k is the thermal conductivity coefficient of 0.6006 Coke/(m** seconds degrees)) initial conditions : t = 0 to 100 degree water boundary conditions : 1. upper and lower walls are free cooling, the third boundary conditions, maintain the temperature around 20 degrees (H = k/h, h for 1) 2. Beibi insulation, The second category boundary conditions graphics format, cylindrical shaft for the cross section of its temperature changes caused animation.
- 2022-05-12 17:55:03下载
- 积分：1
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Lonworks NodeBuilder错误引导
LonWorks NodeBuilder Errors Guide
- 2022-01-25 15:13:59下载
- 积分：1
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影院售票系统完整源码，图形化售票、退票、预定票直观明了...
影院售票系统完整源码，图形化售票、退票、预定票直观明了-cinema ticketing system integrity source, graphical tickets, refunds, scheduled votes intuitive understanding
- 2022-06-28 08:57:56下载
- 积分：1
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VC++ to write with the calculation of MD5 value of the dynamic library, is the s...
用VC++写的计算MD5值的动态库，是源代码哟，可加入自己的程序中进行密码的加密，呵，喜欢的下-VC++ to write with the calculation of MD5 value of the dynamic library, is the source code yo can add it to your program the password encryption, Oh, like the next
- 2023-07-23 03:05:04下载
- 积分：1
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用Ｃ写的ＧＰＳ测试软件，对于开发者回有很大的帮助
用Ｃ写的ＧＰＳ测试软件，对于开发者回有很大的帮助
- 2022-02-02 15:00:26下载
- 积分：1
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一个简单的心理学测试软件.用C++ MFC编写.
一个简单的心理学测试软件.用C++ MFC编写.-a simple psychological test software. MFC C preparation.
- 2022-02-28 13:03:13下载
- 积分：1
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个人财政支出管理的关键源程序代码，已经调试
个人财政支出管理的关键源程序代码，已经调试-Personal financial expenditure management the key to source code, have been debug
- 2022-02-09 22:00:27下载
- 积分：1
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Single round robin tournament players winning sequence to solve the problem name...
单循环赛中选手胜负序列求解问题
名称：单循环赛中选手胜负序列求解问题
内容：有n个选手 P 1 ,P 2 ,P 3 ,… ,P n 参加了的单循环赛，每对选手之间非胜即负。现要求求出一个选手序列 P 1 ,P 2 ,P 3 ,… ,P n , 使其满足 P i 胜 P i+ 1 (i=1,… ,n-1) 。
-Single round robin tournament players winning sequence to solve the problem name: the outcome of single round-robin tournament players to solve the problem sequence elements: There are n-player P 1, P 2, P 3, ..., P n participated in a single round-robin between each pair of players Non-win or negative. Players are now required to find a sequence of P 1 " , P 2" , P 3 " , ..., P n" , to meet the P i " W P i+ 1" (i = 1, ..., n-1).
- 2022-04-01 08:15:51下载
- 积分：1
