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CELP编码器之固定码本搜寻方法之研究.pdf
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约瑟夫（Joeph）问题的一种描述是：编号为1,2,…,n的n个人按顺时针方向围坐一圈，每人持有一个密码（正整数）。一开始任选一个正整数作为报数上限值m，从第一...
约瑟夫（Joeph）问题的一种描述是：编号为1,2,…,n的n个人按顺时针方向围坐一圈，每人持有一个密码（正整数）。一开始任选一个正整数作为报数上限值m，从第一个人开始按顺时针方向自1开始顺序报数，报到m时停止报数。报m的人出列，将他的密码作为新的m值，从他在顺时针方向上的下一个人开始重新从1报数，如此下去，直至所有人全部出列为止。试设计一个程序求出出列顺序。-Joseph (Joeph) a description of the problem is: numbered 1,2, ..., n, n individuals sitting clockwise circle, each holding a password (positive integer). An optional start a positive integer as the number of reported upper limit of m, from the first person to embark on the clockwise direction starting from a reported sequence number, to report the number of m stop reported. Those who reported m out of the column, his password as the new m value, from his home in a clockwise direction on the next person started to re-reported from a few, and so on, until all of the column until all the up. Try a program designed to find out the column order.
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基于Fuzzy－PID的供电站度控制系统的研究
基于Fuzzy－PID的供电站度控制系统的研究-Based on the Fuzzy-PID control station power supply system
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关于：Java2核心技术卷一 配套源码。
关于：Java2核心技术卷一 配套源码。-on : Volume I Java2 core technology supporting FOSS.
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Stepper motor control module, stepper motor control module. VHDL description of...
步进电机控制模块，步进电机控制模块。VHDL描写的步进电机控制模块-Stepper motor control module, stepper motor control module. VHDL description of the stepper motor control module
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C++ Stl detailed development standards manual is very detailed, school STL a goo...
C++ Stl标准详细开发手册，内容非常详细，学STL的好帮手-C++ Stl detailed development standards manual is very detailed, school STL a good helper
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简单教程简单c语言AVR教程简单教程简单 c语言AVR教程
简单教程简单c语言AVR教程简单教程简单 c语言AVR教程-test of c
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j2se1.5.chm中文版，对于e文不好的可是个不错的参考资料。
j2se1.5.chm中文版，对于e文不好的可是个不错的参考资料。-j2se1.5.chm Chinese version of the text for e bad but a good reference.
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J2ME in a Nutshell
J2ME in a Nutshell -J2ME in a Nutshell ......
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beginners should look at
初学者就应该-beginners should look at
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