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基于matlab编程,仿真。matlab编程百例有助于熟悉matlab基本编程命令,最好成为编程高手。小数据量法求lyapunov指数源程序,可以减轻做混沌控制...
基于matlab编程,仿真。matlab编程百例有助于熟悉matlab基本编程命令,最好成为编程高手。小数据量法求lyapunov指数源程序,可以减轻做混沌控制与同步研究的编程苦恼。-Matlab-based programming, simulation. 100 cases of familiar programming matlab help matlab command of basic programming, preferably as a programming expert. Method of small amount of data source lyapunov index can be done to alleviate study of chaos control and synchronization of programming distress.
- 2022-09-04 00:00:03下载
- 积分:1
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LM629运动控制器操作,在自动机器人运行成功,主控为MSP430。
LM629运动控制器操作,在自动机器人运行成功,主控为MSP430。-LM629 motion controller to operate in automatic robot run success, master for the MSP430.
- 2022-03-30 21:28:00下载
- 积分:1
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图片播放器 图片播放器图片播放器 flash+xml
图片播放器 图片播放器图片播放器 flash+xml-Picture picture player player player picture flash+ Xml
- 2022-12-30 21:25:05下载
- 积分:1
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数值分析要求:第二题编成命令文件即可,其中阶乘可以单独编成函数文件在命令文件中调用,也可以直接在你所编的命令文件中利用循环语句直接计算;
第四题编成通用的...
数值分析要求:第二题编成命令文件即可,其中阶乘可以单独编成函数文件在命令文件中调用,也可以直接在你所编的命令文件中利用循环语句直接计算;
第四题编成通用的程序,建议编成函数文件。提示:可以把多项式的系数和所需要求解的点设为参数。-Numerical Analysis of requirements: the second title of the command file can be compiled, which can factorial function into a separate file in order to call the document can also be made directly in your document, use the command loop direct calculation into fourth title common procedures, the proposed document into function. Tip: polynomial coefficients can be requested and the required parameters set point solution.
- 2022-01-25 22:12:15下载
- 积分:1
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本文件里面是Costas环跟踪信号的几幅图,对于加深理解有所一定的帮助。...
本文件里面是Costas环跟踪信号的几幅图,对于加深理解有所一定的帮助。
- 2022-11-03 09:50:02下载
- 积分:1
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SSD5练习推荐1
ssd5 exercise recomended 1
- 2022-03-14 20:52:06下载
- 积分:1
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彩票号码筛选的程序
彩票号码筛选的程序-lottery number Screening procedures
- 2022-02-01 12:39:57下载
- 积分:1
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购物车主要是为广大网上顾客购物的资源平台。购物车主要目标是建设在网上对用户进行信息服务互动平台。...
购物车主要是为广大网上顾客购物的资源平台。购物车主要目标是建设在网上对用户进行信息服务互动平台。-If the owner to the general resources of the Internet platform to customers. The main goal is to Cart online construction information service user interaction platform.
- 2022-02-13 15:40:44下载
- 积分:1
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本设计的目的是通过设计和调试一个简单的文件系统,主要是模拟文件操作命令的执行,来模拟文件管理,使学生对主要文件操作命令的实质和执行过程有比较深入的了解,掌握它们...
本设计的目的是通过设计和调试一个简单的文件系统,主要是模拟文件操作命令的执行,来模拟文件管理,使学生对主要文件操作命令的实质和执行过程有比较深入的了解,掌握它们的基本实施方法。具体要求如下:
(1) 设计一个支持n个用户的文件系统,每个用户可拥有多个文件:
(2) 采用二级或二级以上的多级文件目录管理;
(3) 对文件应设置存去控制保护方式,如“只能执行”、“允许读”、“允许写等”;
(4) 系统的外部特征应接近于真实系统,可设置下述文件操作命令:
命 令 功 能 命 令 功 能
Create 建立文件 Read 读文件
Open 打开文件 Write 写文件
Close 关闭文件 Copy 复制文件
Delete 撤消文件 Directory 查询目录
(5) 通过键盘使用该文件系统,系统应显示操作命令的执行结果。-the purpose of this design is by designing and debugging a simple file system, main operation is simulated documents the execution of the order to simulate document management, enable students to the main document commands the substance and the implementation process of a more in-depth understanding, They grasp of the basic method. Specific requirements are as follows : (1) design a support n user file system, each user can have multiple files : (2) use of two or more than two multi-level directory management; (3) the document should be set up to deposit control and protection methods, such as "the only
- 2023-04-23 12:45:04下载
- 积分:1
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Single round robin tournament players winning sequence to solve the problem name...
单循环赛中选手胜负序列求解问题
名称:单循环赛中选手胜负序列求解问题
内容:有n个选手 P 1 ,P 2 ,P 3 ,… ,P n 参加了的单循环赛,每对选手之间非胜即负。现要求求出一个选手序列 P 1 ,P 2 ,P 3 ,… ,P n , 使其满足 P i 胜 P i+ 1 (i=1,… ,n-1) 。
-Single round robin tournament players winning sequence to solve the problem name: the outcome of single round-robin tournament players to solve the problem sequence elements: There are n-player P 1, P 2, P 3, ..., P n participated in a single round-robin between each pair of players Non-win or negative. Players are now required to find a sequence of P 1 " , P 2" , P 3 " , ..., P n" , to meet the P i " W P i+ 1" (i = 1, ..., n-1).
- 2022-04-01 08:15:51下载
- 积分:1