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of course this book is source code trace
of course this book is source code trace
- 2022-07-01 03:52:07下载
- 积分:1
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用C #农民实用软件
这是一个基于C语言的小型项目。
- 2022-05-13 03:16:32下载
- 积分:1
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适用于初级开发人员,本文档主要用于JavaScript与HTML实用教程。...
适用于初级开发人员,本文档主要用于JavaScript与HTML实用教程。-Applicable to junior developers, this document is mainly used JavaScript and HTML tutorials and practical.
- 2022-04-07 17:20:54下载
- 积分:1
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校园管理项目
类型:项目
- 2022-02-15 17:46:54下载
- 积分:1
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simple hospital management system
简单的医院住院管理系统-simple hospital management system
- 2023-07-03 09:05:04下载
- 积分:1
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软件工程理论报告,重点是以理论知道为主.
希望对大家有帮助...
软件工程理论报告,重点是以理论知道为主.
希望对大家有帮助-software engineering theory, focus mainly on theoretical know. We hope to help
- 2023-06-25 21:35:03下载
- 积分:1
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Here are two newest published articles talking about joint source channel coding...
Here are two newest published articles talking about joint source channel coding, in which source coding is invovled scalable video coding. They are very useful for people who are doing research about it. -Here are two newest published articles talking about joint source channel coding, in which source coding is invovled scalable video coding. They are very useful for people who are doing research about it.
- 2022-02-27 02:45:57下载
- 积分:1
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液晶驱动程序
Driver for Liquid Crystal s
- 2022-02-05 19:27:32下载
- 积分:1
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这是一个多年老程序员的经验总结,做软件开发不得不看的好东东哦...
这是一个多年老程序员的经验总结,做软件开发不得不看的好东东哦-This is a multi-year experience in the old programmers, software developers have done a good look at the Eastern Oh
- 2022-03-12 19:49:30下载
- 积分:1
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C 计算器代码
/ * mustafasırrıinci * /
#include < stdio.h >
#include < stdlib.h >
#include < math.h >
int main ()
{
浮 int1 int2,结果 ;
char 操作 ;
printf("CALCULATORn") ;
开始:
printf ("nnEnter 两个整数 please.n") ;
printf("1.integer:") ;
scanf ("%f"& int1) ;
printf("2.integer:") ;
scanf ("%f"& int2) ;
选择:
printf ("nenter 操作的符号。") ;
printf ("naddition: + nsubtraction:-nmultiplication: * ndivision: /nexponention: ^ nto 退出:! n") ;
scanf ("%s"& 操作) ;
虽然 (操作! = "!")
{
switch(operation)
{
案件 "+":
结果 = int1 + int2 ;
打破 ;
案件 "-":
结果 = int1-int2 ;
打破 ;
案件 " *":
结果 = int1 * int2 ;
打破 ;
- 2022-08-13 04:26:33下载
- 积分:1