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高精度幂计算，北京大学ACM OJ上的Exponetiation
高精度幂计算，北京大学ACM OJ上的Exponetiation-Exponentiation
- 2022-03-21 11:44:04下载
- 积分：1
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a algorithm for short time fourier transform
一种短时傅立叶变换的算法.并利用短时傅立叶变换画图-a algorithm for short time fourier transform
- 2022-04-26 17:11:05下载
- 积分：1
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算法导论 -快速排序
利用C++编写的快速排序，重要思想是利用分治法对数组元素进行比较。其效率是几种排序中最好的。编程的时候关键是要注意索引。对于比较的数，可以选择第一个或者是最后一个元素。文件是与其它的排序算法写在一个工程下的，因此读者需要自己创建新的项目
- 2023-08-27 00:50:04下载
- 积分：1
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16位的CRC程序
用c语言写的求取16位的CRC程序，入口参数： data -- 需要校验的数组 length -- 数组中字节的个数
- 2022-08-08 18:54:46下载
- 积分：1
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一个多功能计算器calc，包含了代数运算、矩阵运算等功能
一个多功能计算器calc，包含了代数运算、矩阵运算等功能-A multi-function calculator calc, contains algebra, matrix operations and other functions
- 2022-07-24 15:01:03下载
- 积分：1
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The cart with an inverted pendulum, shown below, is "bumped" with an impulse
f...
The cart with an inverted pendulum, shown below, is "bumped" with an impulse
force, F. Determine the dynamic equations of motion for the system, and lin
earize about the pendulum s angle, theta = Pi (in other words, assume that p
endulum does not move more than a few degrees away from the vertical, chosen
to be at an angle of Pi). Find a controller to satisfy all of the design re
quirements given below.
-The cart with an inverted pendulum, shown below, is "bumped" with an impulse force, F. Determine the dynamic equations of motion for the system, and lin earize about the pendulum s angle, theta = Pi (in other words, assume that p endulum does not move more than a few degrees away from the vertical, chosen to be at an angle of Pi). Find a controller to satisfy all of the design re quirements given below.
- 2022-03-17 02:37:20下载
- 积分：1
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根据ASCII码输出汉字的一个程序！！希望对大家有所帮助
根据ASCII码输出汉字的一个程序！！希望对大家有所帮助
- 2022-09-19 17:05:03下载
- 积分：1
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刚才弄错了，这才是第二个源码，可以实现输入一二叉树的前序与中序，输出其后序...
刚才弄错了，这才是第二个源码，可以实现输入一二叉树的前序与中序，输出其后序-have just made a mistake, this is the second source, can achieve an input sequence of binary tree with the sequence, then the output sequence
- 2022-03-04 21:26:50下载
- 积分：1
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Interest Calculator
编写visualbasic
- 2022-02-04 06:02:37下载
- 积分：1
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路由器最短路径测试源代码！
路由器最短路径测试源代码！-Shortest Path router test source code!
- 2022-01-26 00:10:38下载
- 积分：1
