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With the human genome project implementation, through genome sequencing, protein...
随着人类基因组计划的实施,通过基因组测序,蛋白质序列测定结构解析等实验,分子生物学家提供了大量的有关生物分子的原始数据,需要利用现代计算技术对这些原始数据进行收集、整理、管理以便于检索使用。而为了解释和理解这些数据,还需要对数据进行比对、分析,建立计算模型,进行仿真、预测与验证,因而出现生物信息学,它的出现,极大的促进了分子生物学的发展。-With the human genome project implementation, through genome sequencing, protein sequencing experiments such as structural analysis, molecular biologists to provide a large amount of biological molecules of the original data, the need to use modern technology to these raw data collection, collation and management in order to facilitate retrieval use. To explain and understand these data, and data need to be compared to analysis, model, simulation, prediction and validation, therefore, bioinformatics, and its emergence has greatly promoted the development of molecular biology.
- 2022-09-17 05:10:03下载
- 积分:1
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多进程多线程
多进程,多线程,VC++MFC模拟多进程并发死锁,界面友好,功能多,独立打包,保证可解压,内含大量源码,网上搜集而来。一共10几包,每个包几十兆。 暴风压力测试2010(V7.0)源码.RAR 超级下载.zip 窗体透明、窗体上控件和DC绘图不透明.rar 大型多媒体视频会议服务器端和客户端源码VC.zip 带加密功能的SQLite3.3.6封装类 .rar 点对点多线程断点续传软件《传圣》源代码.rar 断点续下.zip 多个 请点击左侧文件开始预览 !预览只提供20%的代码片段,完整代码需下载后查看 加载中 侵权举报
- 2022-12-11 03:45:03下载
- 积分:1
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stm32 MPU6050例子
资源描述stm32 MPU6050例子 陀螺仪进行姿态解算,涉及到信号采集,姿态解算。卡尔曼滤波等多种算法,,,
- 2022-03-25 06:10:47下载
- 积分:1
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神经网络和智能信号处理
里面是很多智能算法的doc版资料,此外还有信号处理的方法.如BP,SOM,RBF,混沌神经网络等等,适合初学者
- 2022-07-13 05:33:26下载
- 积分:1
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科学与工程数值计算算法
1、本书附赠的光盘包含了本书中全部的源代码。使用时只需将相应的目录拷贝到您的硬盘中。
注意 拷贝到硬盘上的源文件的属性如果...
科学与工程数值计算算法
1、本书附赠的光盘包含了本书中全部的源代码。使用时只需将相应的目录拷贝到您的硬盘中。
注意 拷贝到硬盘上的源文件的属性如果成为只读的,在编译之前应该将它们的属性改为可读写的。
2、光盘各目录中的内容如下所示:
光盘目录 内容说明
SourceChapterN 第N章的所有示例工程源程序
SourceClasses 本书所有算法类的源程序
SourceLib 集成本书所有算法的静态库文件
SourceDll 集成本书所有算法的动态库文件
-Science and Engineering numerical algorithm 1, this book comes with a CD-ROM contains all the book s source code. Simply use the corresponding copy of the directory to your hard drive. Note to copy the source files on your hard disk becomes read-only attribute in the compiler prior to their properties should be changed to read and write. 2, CD-ROM contents of the directory as follows: CD-ROM directory description SourceChapterN the first chapter all the examples of N source project SourceClasses algorithm book all types of source book SourceLib integrated all of the static algorithm library file SourceDll integrated all book algorithm for dynamic library files
- 2023-08-03 22:30:03下载
- 积分:1
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用C写的,在VC上编译通过,可以查看运行结果,代码没写注释...
用C写的,在VC上编译通过,可以查看运行结果,代码没写注释-written in C, compiled by VC can see the operational results, I did not write code Notes
- 2022-01-22 02:25:43下载
- 积分:1
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按照既定的步长,输入后筛选已有数据 筛选后根据变化,再次筛选...
按照既定的步长,输入后筛选已有数据 筛选后根据变化,再次筛选-accordance with the established step, the imported data has been selected according to changes after the screening, selection again
- 2022-08-31 18:05:04下载
- 积分:1
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C #写三元线性回归方程,可以计算出简单的线性关系。
C#写的三元线性回归方程,可以计算简单的线性回归,第一次写,请包涵。-C# Written ternary linear regression equation, can calculate the simple linear regression, the first to write, please bear with me.
- 2022-07-13 01:16:14下载
- 积分:1
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四重奏:一个理论的定理描述的著名四重奏定理";,&……
四方定理描述: 在数论中有一个著名的“四方定理”,它的含义是: 所有自然数至多只要用四个数的平方和就可以表示。 要求: 该题是一个定理,我们不是去证明它,而是要求同学们编程 序来验证该定理的正确性。 输入: 用户从键盘任意输入一个自然数。 输出: 给出满足四方定理中的至多四个自然数。-Quartet theorem Description : Number Theory in a famous "Quartet Theorem," meaning it is : all natural number can use up to four the number of square and can be expressed. Requirements : The title is a theorem, we will prove it, but to require the students programmed to verify the correctness of the theorem. Input : arbitrary user input from the keyboard to a natural number. Output : the Quartet is to meet the theorem up to four natural number.
- 2022-08-12 22:17:17下载
- 积分:1
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Check1 (0). Caption = "soap" Check1 (1). Caption = "soap" Ch...
Check1(0).Caption = "香皂" Check1(1).Caption = "肥皂" Check1(2).Caption = "牙膏" Check1(3).Caption = "洗衣粉" Label1(0).Caption = "5.8元" Label1(1).Caption = "2.5元" Label1(2).Caption = "7.9元" Label1(3).Caption = "6.4元"-Check1 (0). Caption = "soap" Check1 (1). Caption = "soap" Check1 (2). Caption = "toothpaste" Check1 (3). Caption = "detergent" Label1 (0). Caption = "5 .8 million "Label1 (1). Caption = "2.5 yuan" Label1 (2). Caption = "7.9 yuan" Label1 (3). Caption = "6.4 yuan"
- 2022-01-25 16:20:06下载
- 积分:1