-
2004042323420918natas,从事局域网开发，多媒体技术工程师
2004042323420918natas,从事局域网开发，多媒体技术工程师- 2004042323420918natas,who is engaged in the development of the LAN, engineer of the multimedia technology
- 2022-02-10 11:43:39下载
- 积分：1
-
基于 Web 的版本检查的程序的例子
基于 Web 的版本检查的程序的例子--An example of program of version checking which is based on web
- 2022-06-27 15:49:50下载
- 积分：1
-
Operating system, curriculum design, page
操作系统课程设计，页面淘汰算法以及作业调度算法的演示程序，界面美观，简单易懂，实现功能强大。-Operating system, curriculum design, page-out algorithms and job scheduling algorithm demo program, beautiful interface, easy to understand. To achieve powerful.
- 2022-05-22 17:00:39下载
- 积分：1
-
This code find object in map you need
This code find object in map you need
- 2022-03-07 07:29:05下载
- 积分：1
-
根据给定的对象和路径,获得其子孙成员
根据给定的对象和路径,获得其子孙成员-According to the objects and paths, access to their children and grandchildren members
- 2022-03-22 03:35:33下载
- 积分：1
-
这是一个SDK程序。本程序跟踪显示鼠标的坐标位置，同时，若有鼠标操作，可在窗口标题栏中显示操作信息，要是在窗口客户区中进行双击，就会在双击位置点上显示位置信息。...
这是一个SDK程序。本程序跟踪显示鼠标的坐标位置，同时，若有鼠标操作，可在窗口标题栏中显示操作信息，要是在窗口客户区中进行双击，就会在双击位置点上显示位置信息。此外，客户中还有两个位图，当鼠标移动到位图上时，就会改变为自己定义的光标。该程序适合Win32编程初学者，内含大量的中文注释。-SDK This a process. This program tracking shows the coordinates of the mouse position, and if the mouse operation, the window title bar shows operating information, if the window area for customers double-click, double-click will be the point location shown on the location information. In addition, customers there are two bitmap, when the mouse movement on the plan in place, they will change their definition of the cursor. The program suitable for beginners Win32 programming, with a lot of Chinese Notes.
- 2022-03-19 01:22:51下载
- 积分：1
-
用于椭圆和直线的检测
用于直线和椭圆的检测，检测效果不错，查全率较高，为亚像素精度。
- 2023-07-08 12:45:03下载
- 积分：1
-
用VC＋＋，OpenGL和CG在GPU
上实现保守光栅化
用VC＋＋，OpenGL和CG在GPU
上实现保守光栅化-Using VC , OpenGL and CG in the GPU to achieve conservative rasterization
- 2023-07-18 13:55:03下载
- 积分：1
-
约瑟夫环（Joseph）问题的一种描述是：编号为1，2，…，n的n个人按顺时针方向围坐一圈，每人持有一个密码（正整数）。一开始人选一个正整数作为报数上限值m，从...
约瑟夫环（Joseph）问题的一种描述是：编号为1，2，…，n的n个人按顺时针方向围坐一圈，每人持有一个密码（正整数）。一开始人选一个正整数作为报数上限值m，从第一个人开始按顺时针方向自1开始顺序报数，报到m时停止报数。报m的人出列，将他的密码作为新的m值，从它在顺时针方向的下一个人开始重新从1报数，如此下去，直至所有人全部出列为止。试设计一个程序求出出列顺序-Joseph Central (Joseph) a description of the problem is: numbered 1,2, ..., n of n individuals according to a clockwise direction around a circle, each holding a password (positive integer). The beginning of a positive integer as a candidate at a number of upper limit of m, from the first individual to embark on the clockwise direction since the beginning of the order of 1 is reported the number of stops required to report back at a few m. Those who reported m out of his password as the new value of m, in a clockwise direction from the next person to start off again from the 1, and so on, until all that out until all. Try to design a procedure to derive the column order
- 2022-02-10 01:58:28下载
- 积分：1
-
图像处理的必备源码
图像处理的必备源码-image processing essential source
- 2022-03-12 02:50:18下载
- 积分：1
