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C++源代码实现的非对称算法（RSA）
C++ 源代码实现 非对称算法（RSA）-C++ Source code to achieve asymmetric algorithms (RSA)
- 2022-02-02 15:12:50下载
- 积分：1
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TRegware时间炸弹，可以根据自己需要调整。(有源代码）工作在：D5 D6。作者：Winston Kotzan。...
TRegware时间炸弹，可以根据自己需要调整。(有源代码）工作在：D5 D6。作者：Winston Kotzan。-TRegware time bombs, can be adjusted according to their own. (Source code) work: D5 D6. Author: Winston Kotzan.
- 2022-02-28 17:31:49下载
- 积分：1
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解加密的zip文件的密码的程序
解加密的zip文件的密码的程序 -Cracking encrypted zip file s password
- 2022-01-22 16:33:00下载
- 积分：1
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对音频信号分帧加窗,对每帧进行三阶小波变换,取其逼近系数平均值(一般为零).在此嵌入二值图像 并有对潜入水印信号进行盲检,恢复其嵌入水印...
对音频信号分帧加窗,对每帧进行三阶小波变换,取其逼近系数平均值(一般为零).在此嵌入二值图像 并有对潜入水印信号进行盲检,恢复其嵌入水印-Sub-frame of the audio signal increases the Hamming window for each frame impletment third-order wavelet transform, whichever is close to the average coefficient (usually zero). according to this embedding binary image and resume its embedded watermark from the watermark signal by the Blind detection
- 2022-02-06 17:36:19下载
- 积分：1
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Well
著名图论问题之一。邮递员从邮局出发送信，要求对辖区内每条街，都至少通过一次，再回邮局。在此条件下，怎样选择一条最短路线?此问题由中国数学家管梅谷于1960年首先研究并给出算法，故名。-Well-known graph theory problems. Postman deliver a letter from the post office proceed to require every street within the right area, at least through the time, return to post office. Under these conditions, how to select a shortest route? This issue by the Chinese mathematician Mei Gu tube study in 1960, and gives the first algorithm, hence the name.
- 2022-06-01 03:25:54下载
- 积分：1
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I do a small code, which use cryptography to the spread of the Internet are oper...
本人做的一个小代码，密码学里面要用到的，网上流传的都是运行错误的，这个绝对可以-I do a small code, which use cryptography to the spread of the Internet are operational errors, This can definitely
- 2022-03-16 21:52:36下载
- 积分：1
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Base64 codec demo program
Base64 编解码演示程序 -Base64 codec demo program
- 2022-12-15 14:40:03下载
- 积分：1
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笔者长期从事移动通信系统的无线链路调制与解调、物理层实现方面的工作。在移动通信GSM系统中，我们进行语音或者业务信道解调时，都会遇到CRC的求解。通常在硬件DS...
笔者长期从事移动通信系统的无线链路调制与解调、物理层实现方面的工作。在移动通信GSM系统中，我们进行语音或者业务信道解调时，都会遇到CRC的求解。通常在硬件DSP实现时，特别是40位CRC求解时候，由于生成多项式有41项，DSP最大一次能处理40位，所以使用单个寄存器会遇到一些困难，那么以下这个程序将会解决这一困难（这是针对定点DSP、C55xx的编程实现方法）。-The author has long been engaged in mobile communication system modulation and demodulation of wireless links, the physical layer to achieve work. GSM in the mobile communications system, we have a voice or channel demodulation operations, it will encounter the solution of CRC. DSP hardware usually realize, especially when solving the 40 CRC, as the generation polynomial has 41, DSP can handle the largest 40, so using a single register may encounter some difficulties, then following this process will solve this One difficulty (which is for fixed-point DSP, C55xx realize programming methods).
- 2022-06-18 05:18:56下载
- 积分：1
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MD5加密，已经封装成一个C++类，只要调用该类就可方便使用
MD5加密，已经封装成一个C++类，只要调用该类就可方便使用-This C++ class serves as a wrapper for the Message Digest 5 code described in the Internet RFC 1321.
- 2022-09-22 09:15:03下载
- 积分：1
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安装时修改执行文件记录硬件配置参数从而做唯一安装标志防止非法复制...
安装时修改执行文件记录硬件配置参数从而做唯一安装标志防止非法复制- Installs when revises the execution file recording hardware
disposition parameter thus to do only installs the symbol to prevent
illegal duplicates
- 2022-03-12 19:01:03下载
- 积分：1
