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用龙贝格方法求积分
用龙贝格方法求积分-Romberg method used for points
- 2023-03-22 23:05:03下载
- 积分：1
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这是一个蝶行运算单元,是做FFT的最基本的单元
这是一个蝶行运算单元,是做FFT的最基本的单元-This is a butterfly OK Operational unit, which is doing the most basic FFT modules
- 2022-03-09 16:24:28下载
- 积分：1
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三维张量在不同坐标系的转换可用于昼夜…
三维张量在不同坐标系统的变换，可用于各向异性介质的介电张量的旋转等问题-3D tensor in different coordinate systems transformation can be used in the dielectric anisotropy tensor rotation problems
- 2022-08-15 05:23:31下载
- 积分：1
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典型的一阶马尔科夫信号产生程序
AR(1)模型建模示例，由于AR(1)简单故没有复杂的建模流程，所以此例仅做了解，AR(1)模型的参考，顺便也可以熟悉一下系统辨识工具箱，一阶马尔科夫程序，可以用于有色噪声等。
- 2023-05-30 15:00:03下载
- 积分：1
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a new numerical algorithm
一种新型的数值求解算法-a new numerical algorithm
- 2022-12-01 11:45:03下载
- 积分：1
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Health numerical integration Simpson has been compiled WITH TC 2.0 environment t...
辛普生数值积分，已在TC2.0环境中编译通过-Health numerical integration Simpson has been compiled WITH TC 2.0 environment through
- 2022-02-04 18:50:30下载
- 积分：1
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this program is continuation of 1laser
this program is continuation of 1laser - can fire 2 lasers rangefinders from MDL simultaneusly and then registers measured distance to file - very useful for photogrametry-this program is continuation of 1laser- can fire 2 lasers rangefinders from MDL simultaneusly and then registers measured distance to file- very useful for photogrametry
- 2022-03-25 19:09:06下载
- 积分：1
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系统辨识，递推最小二乘法（RLS）辨识方法。
系统辨识中，递推最小二乘估计（RLS）是辨识模型阶次的一个重要的算法。该程序通过实现该算法，得到模型阶次的估计值以及相关参数值。-system identification, recursive least squares estimation (RLS) identification model is of the order of an important algorithm. The program through the realization of the algorithm, to be model order and the estimated value of the relevant parameters.
- 2022-07-05 08:15:06下载
- 积分：1
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TI DSP TMS320F280x external interrupt routines.
TI DSP TMS320F280x 外部中断例程。-TI DSP TMS320F280x external interrupt routines.
- 2022-02-21 10:14:46下载
- 积分：1
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In this paper, the Monte Carlo method to equation y = sin (x)+ X with the equati...
本文采用蒙特卡洛方法，将方程y=sin(x)+x与方程y=cos(x)+x之间的曲线包络面积求解出来。-In this paper, the Monte Carlo method to equation y = sin (x)+ X with the equation y = cos (x)+ X between the envelope curve out an area to solve.
- 2022-01-25 23:23:06下载
- 积分：1
