登录
首页 » C » stm32手写识别

stm32手写识别

于 2022-05-23 发布 文件大小:9.71 MB
0 184
下载积分: 2 下载次数: 1

代码说明:

基于stm32zet6的手写识别程序源码 一套完整的手写识别源码,可以识别数字、字母和汉字,识别率还不错

下载说明:请别用迅雷下载,失败请重下,重下不扣分!

发表评论

0 个回复

  • bmp2jpeg&jpegcoding
    bmp转换为jpeg,jpeg压缩的源代码 程序用vc实现了bmp图片转换成jpeg图片(converted to jpeg bmp, jpeg compression source code procedures used vc realized bmp images converted into jpeg photos)
    2020-11-28 10:29:30下载
    积分:1
  • HotKey
    通过VS2010建立一个MFC对话框程序,通过这个对话框程序来体现热键的开发过程,简单易懂(By establishing a VS2010 MFC dialog procedures, through this dialog box to reflect the hotkey program development process, easy to understand)
    2013-11-03 15:56:22下载
    积分:1
  • cc1120
    CC1120 芯片的收发驱动程序,STM32,STC8051,ATSAM21.测试通过,已运用到产品上。(CC1120 chip driver, STM32, STC8051, ATSAM21. passed the test, has been applied to the product.)
    2020-09-19 11:27:57下载
    积分:1
  • GaussNoise
    生成高斯白噪声的程序,可以自由设置sigma等大小, 还有四元数计算(the program of gaussian noise)
    2017-08-01 10:28:55下载
    积分:1
  • STM32-ADS1247
    stm32硬件SPI方式控制ADS1247采样驱动程序(stm32 hardware SPI driver controls the ADS1247 sampling)
    2021-01-18 12:08:43下载
    积分:1
  • CAN单向发送
    说明:  A、B两块开发板上电,按开发板A上的按键S1—S4,A板将通过CAN总线向B板发送按键数字信息,B板接收到该信息后通过数码管显示出A版相应的按键值。(A, B two development board power, press the development board A button s1-s4, A board will send key digital information through CAN bus to B board, B board received the information through the digital tube display A corresponding key value.)
    2020-06-20 09:40:01下载
    积分:1
  • xt10-4
    说明:  有两个矩阵a和b,均为2行3列。求矩阵之和。(There are two matrices a and b, are two rows 3. Demand matrices, and.)
    2010-03-17 20:19:01下载
    积分:1
  • MatlabCSharpSample
    C#与Matlab混合编程的例子,用两种方式实现!(C# and Matlab examples of mixed programming, implemented in two ways!)
    2011-07-06 13:00:37下载
    积分:1
  • untitled8
    说明:  基于C++和QT的联合开发,它被用来建立其他的接口学习机制(Based on the joint development of C + + and QT, it is used to establish other interface learning mechanisms)
    2020-03-13 10:58:55下载
    积分:1
  • arithmetic
    求单词个数的三种算法分析 用户任意输入一个字符串 ,求该字符串中包含的单词个数 ,其 中单词以空格分隔。这道题目难度合适,不用理解复杂的概念,纯粹的考察学生解决问题的能力,而且题目看似简单,学 生很有信心能够解决这个问题。每年讲解程序语言基础课或者程序设计高级时 ,都拿这道题目让学生做练习 ,但是学生做 的情况并不乐观 ,因此有必要总结一下 3 种经典解法 ,让初学者也能够体会到程序和算法的乐趣 ,让学生爱上学习。(Find the number of words any of the three algorithms analyze user inputs a string, find the number of words contained in a string, in which words separated by spaces. This question is difficult to project the right, do not understand the complex concepts, students study the pure problem-solving skills, and the subject appears to be simple, the students are confident to solve this problem. Explain each programming language basic course or advanced programming, they all head to take the problem asks students to do exercises, but students do not optimistic, it is necessary to summarize the three kinds of classical solution, so that beginners can understand the procedures and algorithms fun for students to love learning.)
    2011-07-11 18:47:08下载
    积分:1
  • 696516资源总数
  • 106442会员总数
  • 11今日下载