-
讲解在VC＋＋复杂的编程环境下，如何一丝不苟的实现复杂的窗口绘图功能一定要下载学习哦...
讲解在VC＋＋复杂的编程环境下，如何一丝不苟的实现复杂的窗口绘图功能一定要下载学习哦-Explain the complexity of the VC programming environment, how to realize the complexity of meticulously mapping the window function must download to learn Oh
- 2022-02-13 16:08:51下载
- 积分：1
-
从黑白图像转换为RGB图像
convert from bw image to rgb image
- 2022-09-15 02:35:03下载
- 积分：1
-
实现图象的局部放大,移动鼠标可放大不同的部位,鼠标左键缩小图象,右键放大图象...
实现图象的局部放大,移动鼠标可放大不同的部位,鼠标左键缩小图象,右键放大图象-achieve a partial image to enlarge it, move the mouse to enlarge different parts, the left mouse button narrow image, right image to enlarge it
- 2022-06-13 17:40:52下载
- 积分：1
-
VC environment, graphical programming DOE painting straight lines, circles and p...
VC环境下的图形编程
TCAD画直线、圆和多边形的程序-VC environment, graphical programming DOE painting straight lines, circles and polygons procedures
- 2023-03-06 00:40:03下载
- 积分：1
-
包括三个程序，可以实现代立的朱立
包括三个程序,可以实现生成朱力叶集,曼德布罗特集,速度很快!-including three procedures can be achieved Generation Zhu Li Ye set-- Mandelbrot B B sets, very fast!
- 2022-04-28 08:49:18下载
- 积分：1
-
WPF入门源码，具体有三个例子，可提供对WFC的学习帮助
WPF入门源码，具体有三个例子，可提供对WFC的学习帮助-WPF entry source, there are three specific examples, which could provide learning WFC help
- 2022-05-28 14:53:33下载
- 积分：1
-
This is a chess game, the rules of the game similar to Go. Function is not very...
这是一款棋类游戏，游戏规则类似于围棋。功能不是很完全，希望对大家有帮助。-This is a chess game, the rules of the game similar to Go. Function is not very full, and they hope to have everyone help.
- 2023-05-19 18:50:04下载
- 积分：1
-
ImageAnimator类
用于动画处理包含基于时间的帧的图像。
ImageAnimator类
用于动画处理包含基于时间的帧的图像。
-Type of treatment for ImageAnimator animation frame that contains time-based images.
- 2022-06-12 05:25:07下载
- 积分：1
-
Hough变换用来在图象中查找直线。它的原理是：假设有一条与原点距离为s，方向角为θ的一条直线，直线上的每一点都满足方程 s=x*Cosθ+y*Sinθ，利用这...
Hough变换用来在图象中查找直线。它的原理是：假设有一条与原点距离为s，方向角为θ的一条直线，直线上的每一点都满足方程 s=x*Cosθ+y*Sinθ，利用这个事实，我们可以找出某条直线来。这段程序，用来找出图象中最长的直线。-Hough Transformation is used for searching lines in an image . Here is the principle:
Assume there is a line whoes direction is "sita" , and the distance from the origin to this line is s. So each point in this line satisfies the equation : s=x*Cos(sita)+ y*Sin(sita) . We can find out the lines based on this fact.
And this programme is to find out the longest line in the image.
- 2022-09-05 00:30:03下载
- 积分：1
-
Looks like a drawing program, a good look at him the principles of how to achiev...
貌似一个画图的程序，好好看看他的原理，到底怎么实现的，当然你学画图也行。-Looks like a drawing program, a good look at him the principles of how to achieve in the end, of course, drawing you to learn is required.
- 2023-02-23 22:20:03下载
- 积分：1
