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嵌入式软件的电子图书
ebook of Embedded Software using C
- 2022-11-11 15:15:04下载
- 积分:1
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解释如何使用CVS。
To explain how to use CVS.
- 2023-05-17 21:10:02下载
- 积分:1
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WIN2000 Driver Development Guide
win2000驱动开发指南-WIN2000 Driver Development Guide
- 2022-03-19 13:59:11下载
- 积分:1
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支持向量机 张鑫.ppt,比较容易懂,属于入门级的
支持向量机 张鑫.ppt,比较容易懂,属于入门级的-SVM Zhang Xin. Ppt, it was relatively easy to understand, is the entry-level
- 2022-11-30 01:40:04下载
- 积分:1
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gcc 编译器参考大全
gcc 编译器参考大全-gcc compiler reference Daquan
- 2022-05-15 06:16:19下载
- 积分:1
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- 2023-07-03 03:30:04下载
- 积分:1
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背包问题动态规划算法JAVA
给定n种物品和一背包。物品i的重量是wi,其价值为vi,背包的容量为c。问应如何选择装入背包中的物品,使得装入背包中物品的总价...
背包问题动态规划算法JAVA
给定n种物品和一背包。物品i的重量是wi,其价值为vi,背包的容量为c。问应如何选择装入背包中的物品,使得装入背包中物品的总价值最大?
在选择装入背包的物品时,对每种物品i只有两种选择,即装入背包或不装入背包。不能将物品i装入背包多次,也不能只装入部分的物品i。因此,该问题称为0-1背包问题。-Knapsack problem dynamic programming algorithm for a given n species JAVA goods and one backpack. Item i is the weight of wi, the value for vi, knapsack capacity c. Question should be how to choose the items into the backpack, the backpack into the total value of the largest items? In the selection of the items into the backpack, for each of the items i have only two choices, that is loaded or not loaded backpack backpack. Items should not be many times i load backpack can not only part of the goods loaded i. Therefore, the problem known as the 0-1 knapsack problem.
- 2023-04-22 23:20:03下载
- 积分:1
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中国地质大学编写的空间数据库,好不容易才弄到的,现在贡献给大家...
中国地质大学编写的空间数据库,好不容易才弄到的,现在贡献给大家-China University of Geosciences in space database, and managed to only get, and now everyone to contribute
- 2022-02-07 09:57:31下载
- 积分:1
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串口通信的一本好书,可以用于手机编程,非常的实用,大家多多交流...
串口通信的一本好书,可以用于手机编程,非常的实用,大家多多交流-Serial communication a good book can be used for mobile phone programming, very practical, a lot of exchange of U.S.
- 2022-01-26 01:48:03下载
- 积分:1
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Java university practical tutorial version 2 source code, easy to understand
Java大学实用教程第2版程序源代码,便于搞懂书上的例子-Java university practical tutorial version 2 source code, easy to understand
- 2022-04-27 02:11:34下载
- 积分:1