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串口通信PC机应用程序
串口通信PC机应用程序-PC serial communication applications
- 2023-02-25 10:15:03下载
- 积分:1
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自动催费.能够应用在很多领域,如果需要请和我联系,
自动催费.能够应用在很多领域,如果需要请和我联系,-automatic reminders charges. Can be used in many fields, and if necessary please contact me,
- 2022-05-31 13:18:24下载
- 积分:1
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单片机的通用串口接收和发送无线信息,无线接收…
单片机通用串口uart接收与发送无线信息,实现无线接收。-MCU Universal Serial uart receive and transmit a wireless message, wireless receiver.
- 2022-03-14 09:56:41下载
- 积分:1
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用C++写的modbus串口通讯程序,供大家学习参考
用C++写的modbus串口通讯程序,供大家学习参考-C wrote Modbus serial communication program for all learning reference
- 2022-03-29 16:56:22下载
- 积分:1
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是用C语言编写的关于用51单片机控制12864液晶LCD的源程序,适用与交流电压及其谐波的显示
是用C语言编写的关于用51单片机控制12864液晶LCD的源程序,适用与交流电压及其谐波的显示-Is written in C with a 51 on the MCU control 12864 LCD LCD source, application and the display of AC voltage and its harmonic
- 2022-02-20 14:55:38下载
- 积分:1
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integrity of the asynchronous serial communication procedures
完整的异步串行通信的处理程序-integrity of the asynchronous serial communication procedures
- 2022-03-26 18:36:34下载
- 积分:1
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下载工具源代码,用于串口RS232下载,二次下载
下载工具源代码,用于串口RS232下载,二次下载-download source code
- 2022-08-07 05:06:05下载
- 积分:1
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VC的COM口驱动程序,使用了ACTIVEX控件
VC的COM口驱动程序,使用了ACTIVEX控件-VC COM port drivers, the use of Activex Control
- 2022-07-02 09:38:33下载
- 积分:1
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RS编码
CodeWarrior环境例程!
RS编码
CodeWarrior环境例程!-RS CW environmental routines!
- 2022-07-18 21:49:19下载
- 积分:1
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这是非常有挑战性的题目。对于用户输入的任意一个平面函数f(x),绘制出其函数曲线。这里最关键的技术难点就是如何实现计算表达式的值。在《编译原理》和《数据结构》的...
这是非常有挑战性的题目。对于用户输入的任意一个平面函数f(x),绘制出其函数曲线。这里最关键的技术难点就是如何实现计算表达式的值。在《编译原理》和《数据结构》的书中,都有对表达式运算方法的论述。说实在的,在编译型计算机语言中实现对用户输入表达式的运算是非常困难的。需要对表达式进行扫描,去括号,按照运算符的优先级生成2叉树,然后遍历该树生成逆波兰表达式,再然后通过栈的方法进行运算。如果在表达式中再包含有函数的话......描述起来都麻烦,更不要说用程序实现了:-(-This is a very challenging issue. For user input an arbitrary planar function f (x), mapping out its function curves. Here the most critical technical problems is how to achieve calculated the value of the expression. "Compiling Principle" and "data structure," the book, have right of expression Operational discussed. Indeed, the computer language compiler to achieve expression of the user input operation is very difficult. Need to scan expression to the brackets, in accordance with the priority Operators Generation 2-ary tree, and then traverse the tree generated reverse Polish expression, and then through the stack approach to computing. If the expression again contains the function described ...... these are trouble, not to mention t
- 2022-02-25 13:48:40下载
- 积分:1