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Hopfield网络是一种典型的单层反馈网络,这种网络可以分为离散型和连续型两种,Hopfield网络是一个动力学系统,在确定连接权重后,若输入某个向量之后,网...
Hopfield网络是一种典型的单层反馈网络,这种网络可以分为离散型和连续型两种,Hopfield网络是一个动力学系统,在确定连接权重后,若输入某个向量之后,网络将不断演化,一般情况下系统将趋向某一个定态,称为状态空间的不动点吸引子。-Hopfield network is a typical single-layer feedback network, Such networks can be divided into discrete and continuous two, the Hopfield network is a dynamic system, In determining the weights link, and if the importation of a certain vector, the network will continue to evolve Under normal circumstances a system will tend to a steady state, as the state space of fixed point attractor.
- 2023-03-07 16:15:03下载
- 积分:1
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一:需求分析
1. 问题描述
魔王总是使用自己的一种非常精练而抽象的语言讲话,没人能听懂,但他的语言是可逐步解释成人能听懂的语言,因为他的语言是由以下两...
一:需求分析
1. 问题描述
魔王总是使用自己的一种非常精练而抽象的语言讲话,没人能听懂,但他的语言是可逐步解释成人能听懂的语言,因为他的语言是由以下两种形式的规则由人的语言逐步抽象上去的:
-----------------------------------------------------------
(1) a---> (B1)(B2)....(Bm)
(2)[(op1)(p2)...(pn)]---->[o(pn)][o(p(n-1))].....[o(p1)o]
-----------------------------------------------------------
在这两种形式中,从左到右均表示解释.试写一个魔王语言的解释系统,把
他的话解释成人能听得懂的话.
2. 基本要求:
用下述两条具体规则和上述规则形式(2)实现.设大写字母表示魔王语言的词汇 小写字母表示人的语言的词汇 希腊字母表示可以用大写字母或小写字母代换的变量.魔王语言可含人的词汇.
(1) B --> tAdA
(2) A --> sae
3. 测试数据:
B(ehnxgz)B 解释成 tsaedsaeezegexenehetsaedsae若将小写字母与汉字建立下表所示的对应关系,则魔王说的话是:"天上一只鹅地上一只鹅鹅追鹅赶鹅下鹅蛋鹅恨鹅天上一只鹅地上一只鹅".
| t | d | s | a | e | z | g | x | n | h |
| 天 | 地 | 上 | 一只| 鹅 | 追 | 赶 | 下 | 蛋 | 恨 |
-one : a needs analysis. Problem description always use their own fiendish a very concise and abstract language speech Nobody can understand, but the language is gradually explained adult can understand the language, because his language is composed of the following two forms of
- 2022-09-04 11:50:02下载
- 积分:1
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北大密码学课程的课件~密码学基础1
北大密码学课程的课件~密码学基础1-4
讲得通俗易懂。适合初学者自学使用。也可用来辅助读加解密程序或者编程。-Beijing University courses courseware cryptography Cryptography ~ 1-4 speak basic user-friendly. Suitable for beginners to use self-study. Can also be used to support encryption and decryption procedures, or read programming.
- 2022-06-03 14:17:51下载
- 积分:1
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Cheng T112 MCU source code for external MCU Part T112
T112 MCU源程码,用于T112外接MCU篇程,用来驱动模拟屏-Cheng T112 MCU source code for external MCU Part T112-way, used to drive simulation screen
- 2023-07-04 17:15:03下载
- 积分:1
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该方法采用反对称双正交小波分解系数计算视频帧的方向梯度向量,再统计由梯度向量角和模值构成的联合空间二维直方图,然后计算连续帧直方图之间的距离,得到两帧之间的不连
该方法采用反对称双正交小波分解系数计算视频帧的方向梯度向量,再统计由梯度向量角和模值构成的联合空间二维直方图,然后计算连续帧直方图之间的距离,得到两帧之间的不连续值,最后采用自适应阈值分割,检测出镜头边界。-This method is the use of anti-symmetric biorthogonal wavelet decomposition coefficients video frame the direction of gradient vector, and then statistics from the gradient vector angle and modulus values constitute the joint space of two-dimensional histogram, and then calculating the histogram for the distance between frames, by the two frames between the consecutive values, the final adaptive threshold segmentation, shot boundary detected.
- 2022-05-09 05:15:23下载
- 积分:1
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altera cycloneII fpga 的pcb封装图,protel格式的,下载后加载,省得自己画了。...
altera cycloneII fpga 的pcb封装图,protel格式的,下载后加载,省得自己画了。-altera cycloneII fpga the pcb package plans, protel format, download load clinics to save their own a painting.
- 2023-02-23 23:30:03下载
- 积分:1
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10K 0.05 5MHz的频率测量误差。用ATMEGA16实现
10K到5MHz的频率测量,误差在0.05 之内。用ATmega16实现-10K to 5MHz frequency measurement error of 0.05 . Implementation with ATmega16
- 2023-04-11 12:15:03下载
- 积分:1
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软件工程的设计和开发文件,由于本人也不知道怎么回事,所以还请读者自己去斟酌,希望对你们有帮助!...
软件工程的设计和开发文件,由于本人也不知道怎么回事,所以还请读者自己去斟酌,希望对你们有帮助!-software engineering design and development, because I do not know how, therefore, also invited readers to their own discretion, and I hope to have your help!
- 2022-07-22 23:19:42下载
- 积分:1
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此程序是485通信控制程序,在实物中以经调试通过.各项性能指标均合格.
此程序是485通信控制程序,在实物中以经调试通过.各项性能指标均合格.-This program is 485 communication control procedures, in-kind in order to debug passed by. The performance indicators are satisfactory.
- 2022-01-25 17:29:01下载
- 积分:1
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socket communication process, from the client to send a number of characters in...
socket通讯程序,从客户端发送若干字符后在在服务器端接收-socket communication process, from the client to send a number of characters in the server side to receive
- 2022-06-15 01:32:47下载
- 积分:1