登录
首页 » 电子书 » 这是一套操作系统课的课件,内容很全面,讲得不错,很有价值.

这是一套操作系统课的课件,内容很全面,讲得不错,很有价值.

于 2022-07-13 发布 文件大小:3.61 MB
0 207
下载积分: 2 下载次数: 1

代码说明:

这是一套操作系统课的课件,内容很全面,讲得不错,很有价值.-This is a set of courseware class operating system, which is very comprehensive and speak well, very valuable.

下载说明:请别用迅雷下载,失败请重下,重下不扣分!

发表评论

0 个回复

  • NOKIA手机MMS开发手册,全英文的,不是很难读,有点英文基础的人就能看懂。...
    NOKIA手机MMS开发手册,全英文的,不是很难读,有点英文基础的人就能看懂。-Nokia MMS development manuals, the whole English is not hard to read, a little bit based on the English people can understand.
    2022-05-05 20:39:52下载
    积分:1
  • 使用RGB传感器可以测量
    turbity measurement using rgb sensor
    2022-01-22 13:14:07下载
    积分:1
  • 基于JXTA平台的myjxta2_4源代码分析和详细的应用…
    基于JXTA平台的MyJXTA2_4源码分析及应用,详细分析了myjxta的开发源码,涉及了jxta平台的知识-Based on JXTA Platform MyJXTA2_4 source code analysis and application of a detailed analysis of the development of myjxta source, involving the jxta platform of knowledge
    2022-07-24 00:14:07下载
    积分:1
  • 关于pc各种接口的标准文件
    关于pc各种接口的标准文件-pc on a variety of interface standards document
    2023-01-18 06:45:04下载
    积分:1
  • 基于网络光盘库的优先排队模型分析.rar 基于网络光盘库的优先排队模型分析.rar...
    基于网络光盘库的优先排队模型分析.rar 基于网络光盘库的优先排队模型分析.rar-Web-based CD-ROM database analysis of the priority queuing model. Rar network-based CD-ROM database analysis of the priority queuing model. Rar
    2022-03-19 14:37:21下载
    积分:1
  • 易语言时尚编程100例 (一)例程名称:计算编辑框的输入内容的长度 设立本100例教程的目的:把易语言现有的例程都学习一遍,以达到共同脱菜的目的...
    易语言时尚编程100例 (一)例程名称:计算编辑框的输入内容的长度 设立本100例教程的目的:把易语言现有的例程都学习一遍,以达到共同脱菜的目的-Easy programming language 100 cases of fashion (1) Routine Name: Edit the calculation of the input box the length of one hundred cases to establish the purpose of the tutorial: easy to put the existing language routines are studying again in order to achieve the common objective of food from
    2022-11-21 04:30:03下载
    积分:1
  • 这是我收集的有关无线网络的安全的
    这是我收集的有关无线网络的安全的书籍-security_in_wireless_ad_hoc_and_sensor_networks
    2022-02-25 02:56:32下载
    积分:1
  • 转载,一个很好的C语言教材。
    Reshipped,A good C language teaching material.
    2022-06-16 02:50:30下载
    积分:1
  • 一家石油公司计划在主管道中建设一个东向西。PIP…
    某石油公司计划建造一条由东向西的主输油管道。该管道要穿过一个有 n 口油井的油田。从每口油井都要有一条输油管道沿最短路经(或南或北)与主管道相连。如果给定 n口油井的位置,即它们的 x 坐标(东西向)和 y 坐标(南北向),应如何确定主管道的最优位置,即使各油井到主管道之间的输油管道长度总和最小的位置?证明可在线性时间内确定主管道的最优位置,使得给定n口油井的位置,编程计算各油井到主管道之间的输油管道最小长度总和。 -An oil company plans to construct a east to west from the main pipeline. The pipeline to pass through an oil field n wells. Wells from each must have a pipeline along the shortest path (or South or North) connected with the competent Road. If given the location of oil wells in n, that is, their x coordinates (east-west) and y coordinates (north-south), should be how to determine the optimal position in charge of Road, even if the wells to the pipeline in charge of Road between the sum of the smallest length location? proved to be linear time in charge of Road to determine the optimal location, making a given n the location of oil wells, programmed to calculate the well-to-charge of Road between the length of the sum of the smallest oil pipeline.
    2022-10-27 02:45:03下载
    积分:1
  • 用于气和通信的概率和随机过程的解决方案手册…
    Solution manual for < Probability and Random Processes for Electrical and Computer Engineers>> John A. Gubner University of Wisconsin, Madison
    2022-11-01 03:05:03下载
    积分:1
  • 696516资源总数
  • 106554会员总数
  • 12今日下载