-
把链表S中从第m个元素起共n个元素存储到s中,成功返回1,否则返回0int LEN(STRING S)...
把链表S中从第m个元素起共n个元素存储到s中,成功返回1,否则返回0int LEN(STRING S) -S in the list from the first m elements from a total of n elements stored in the s successful one back, otherwise return 0int LEN (STRING S)
- 2022-08-21 01:56:05下载
- 积分:1
-
这是关于信源压缩编码里面比较经典的压缩编码算法
这是关于信源压缩编码里面比较经典的压缩编码算法-Huffman算法的代码!-This is on the inside source coding compare a classic Coding Algorithm-Huffman algorithm code!
- 2023-01-06 00:00:05下载
- 积分:1
-
Interactive platform to create user interfaces, mainly familiar with the use of...
创建用户界面交互平台,主要是熟悉控件的使用 -Interactive platform to create user interfaces, mainly familiar with the use of control
- 2022-07-16 09:29:24下载
- 积分:1
-
0_1背包问题使用一个给定n种去的动态规划解法…
0_1背包问题用动态规划解给定n种物品和一背包。物品i的重量是wi,其价值为vi,背包的容量为c。问应如何选择装入背包中的物品,使得装入背包中物品的总价值最大?
在选择装入背包的物品时,对每种物品i只有两种选择,即装入背包或不装入背包。不能将物品i装入背包多次,也不能只装入部分的物品i。因此,该问题称为0-1背包问题。-0_1 knapsack problem using dynamic programming solution of a given n types of goods and one backpack. Item i is the weight of wi, the value for vi, knapsack capacity c. Question should be how to choose the items into the backpack, the backpack into the total value of the largest items? In the selection of the items into the backpack, for each of the items i have only two choices, that is loaded or not loaded backpack backpack. Items should not be many times i load backpack can not only part of the goods loaded i. Therefore, the problem known as the 0-1 knapsack problem.
- 2023-04-12 03:25:02下载
- 积分:1
-
在MFC应用程序中根据自己的选择显示一个JPG图形文件
在MFC应用程序中根据自己的选择显示一个JPG图形文件-MFC application in accordance with their own choose to display a JPG graphic files
- 2022-09-06 03:55:02下载
- 积分:1
-
一款很好用的打谱软件,可以选择不同的乐器试听你所记的谱.
一款很好用的打谱软件,可以选择不同的乐器试听你所记的谱.-A good fight spectrum of software can choose different instruments Let your mind spectrum.
- 2022-08-18 20:06:35下载
- 积分:1
-
使用CZip和CUnzip压缩VC代码文件和减压
VC下使用CZip和CUnzip压缩和解压文件代码-VC use CZip CUnzip and document compression and decompression code
- 2023-01-08 18:30:04下载
- 积分:1
-
H.263编解码程序
H.263+编解码程序-H.263 codec procedures
- 2022-11-26 23:50:03下载
- 积分:1
-
通信中的压缩、解压缩。利用相对编码的原理,进行前后相减。(编程背景为温室温度测量,限定在正负50以内)。已经编译通过。...
通信中的压缩、解压缩。利用相对编码的原理,进行前后相减。(编程背景为温室温度测量,限定在正负50以内)。已经编译通过。-Communication compression, decompression. The principle use of the relative encoding, carried out before and after the subtraction. (Programming background greenhouse temperature measurement, limited to within plus or minus 50). Has been compiled through.
- 2022-03-26 15:48:22下载
- 积分:1
-
鉴于网上公布的x264调用较为复杂,使很多新手不适,我特意将其进行了简单的封装,并提供了 lib 和 测试程序,该程序已经通过编译,修改 宽高及文件路径等即可运...
鉴于网上公布的x264调用较为复杂,使很多新手不适,我特意将其进行了简单的封装,并提供了 lib 和 测试程序,该程序已经通过编译,修改 宽高及文件路径等即可运行-In view of online publication called the x264 is more complicated, does not make a lot of novice, I made it for a simple package, and provides a lib and test procedures, the procedures have been adopted by the compiler, modify the path wide and so high and documents can be run
- 2022-06-16 03:02:25下载
- 积分:1