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GUI developing circumstance by Trolltech. It can support many APIs and be a good...
Trolltech公司发布的基于C++图形开发环境，支持大量的API，是Linux下的图形界面开发利器。这个版本可以和qt-embedded-2.3.7配合使用。-GUI developing circumstance by Trolltech. It can support many APIs and be a good tool for GUI developing on Linux. This version can be use with qt-embedded-2.3.7.
- 2022-02-15 11:24:04下载
- 积分：1
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using PCMCIA wireless LAN wireless virtual procedures FOSS AP
linux下用PCMCIA无线网卡虚拟无线AP的程序源码-using PCMCIA wireless LAN wireless virtual procedures FOSS AP
- 2022-11-04 03:00:08下载
- 积分：1
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Standard c++ Learning the source code. Uc code there are 15 days c++ Learning co...
标准c++的学习源代码。还有uc代码
15天c++学习代码和4天unix c学习代码
使用gcc编译器，solaris环境，完全通过编译，源自达内科技学习笔记-Standard c++ Learning the source code. Uc code there are 15 days c++ Learning code and four days to learn unix c code using gcc compiler, solaris environment, completely through the compiler, derived from scientific and technological study notes Tatsu
- 2023-06-12 19:05:04下载
- 积分：1
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RoboCup 2005 2D仿真 Brainstormers队 源代码
RoboCup 2005 2D仿真 Brainstormers队 源代码-Brainstormers Source2005
- 2022-06-29 03:48:26下载
- 积分：1
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语音回声消除库
speech echo cancellation library
- 2023-06-06 20:05:03下载
- 积分：1
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linux 指令大全，详细解释了常用的指令的使用权限、方式、参数等。...
linux 指令大全，详细解释了常用的指令的使用权限、方式、参数等。-Encyclopedia of linux commands, explained in detail the use of commonly used commands permissions, methods, parameters and so on.
- 2022-07-08 07:28:56下载
- 积分：1
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串口编程
LINUX下串口编程-serial programming in linux
- 2023-06-18 11:15:04下载
- 积分：1
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用简单的例子实现了用命名管道实现进程间通信
用简单的例子实现了用命名管道实现进程间通信-simple example of the realization of the named pipe used to achieve inter-process communication
- 2022-08-25 17:11:40下载
- 积分：1
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minigui的开发程序，非常典型的程序，在sc2410上跑通了，很漂亮哦了...
minigui的开发程序，非常典型的程序，在sc2410上跑通了，很漂亮哦了-minigui development of procedures, very typical procedure, in the run sc2410 had, oh, a very beautiful
- 2023-07-05 20:30:03下载
- 积分：1
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int show_char(int n, const char *name, chtype code)
{
const int height =...
int show_char(int n, const char *name, chtype code)
{
const int height = 16
int row = 4 + (n height)
int col = (n / height) * COLS / 2
mvprintw(row, col, " *s : ", COLS/4, name)
addch(code)
return n + 1
}- int show_char(int n, const char*name, chtype code)
{
const int height = 16
int row = 4+ (n height)
int col = (n/height)* COLS/2
mvprintw(row, col, "*s : ", COLS/4, name)
addch(code)
return n+ 1
}
- 2023-01-13 11:50:04下载
- 积分：1
