登录
首页 » c » MD5算法VC6.0

MD5算法VC6.0

于 2022-08-07 发布 文件大小:1.61 kB
0 82
下载积分: 2 下载次数: 1

代码说明:

md5:以512位分组来处理输入的信息,且每一分组又被划分为16个32位子分组,经过了一系列的处理后,算法的输出由四个32位分组组成,将这四个32位分组级联后将生成一个128位散列值。  在md5算法中,首先需要对信息进行填充,使其字节长度对512求余的结果等于448.因此,信息的字节长度(bits length)将被扩展至n*512+448,即n*64+56个字节(bytes),n为一个正整数。填充的方法如下,在信息的后面填充一个1和无数个0,直到满足上面的条件时才停止用0对信息的填充。然后,在这个结果后面附加一个以64位二进制表示的填充前信息长度。经过这两步的处理,现在的信息字节长度=n*512+448+64=(n+1)*512,即长度恰好是512的整数倍。这样做的原因是为满足后面处理中对信息长度的要求。  md5

下载说明:请别用迅雷下载,失败请重下,重下不扣分!

发表评论

0 个回复

  • Mathematics
    Only one month to go before the nullarbor demoparty and game development competition takes place! The event will be held at ECU Mount Lawley, School of Computer and Information Science in Perth, Western Australia on Thursday the 23rd of February 2006.
    2006-03-28 11:52:49下载
    积分:1
  • SendStr
    ucos2.83在LPC2148上的例子,使用ADS1.2makefile的编译方式,完整可用的例子。包含多个外设的应用,完全原创(ucos2.83 in LPC2148 examples, the use of compiler ADS1.2makefile way, complete examples available. The application includes a number of peripherals, completely original)
    2008-01-15 13:03:10下载
    积分:1
  • main
    以一个m*n的长方阵表示迷宫,0和1分别表示迷宫中的通路和障碍。设计一个程序,对任意设定的迷宫,求出一条从入口到出口的通路,或得出没有通路的结论。 1.基本要求 (1)首先实现一个以链表作存储结构的栈类型,然后编写一个求解迷宫的非递归程序。求得的通路以三元组(i,j,d)的形式输出。其中:(i,j)指示迷宫中的一个坐标,d表示走到下一坐标的方向。如下图所示迷宫。从入口(1,1)到出口(8,8)的求解结果如下: (1,1)(1,2),(2,2)(3,2)(3,1)(4,1)(5,1)(5,2)(5,3)(6,3)(6,4)(6,5)(5,5)(4,5)(4,6)(4,7)(3,7)(3,8)(4,8)(5,8)(6,8)(7,8)(8,8)(The labyrinth is represented by a m*n rectangular array. 0 and 1 represent the pathways and obstacles in the labyrinth respectively. Design a program for any set of maze, find a way from the entrance to the exit, or draw no conclusion of the path. 1. basic requirements (1) first implement a stack type with linked list as storage structure, then write a non recursive procedure to solve the maze. The path obtained is output in the form of three tuple (I, J, d). Among them: (I, J) indicates a coordinate in the labyrinth, and D indicates the direction of going to the next coordinate. As shown in the labyrinth below. The results obtained from the entrance (1, 1) to the outlet (8, 8) are as follows: (1, 1) (1, 2), (2, 2) (3, 2) (3, 1) (4, 1) (4, 1).)
    2018-07-03 13:15:46下载
    积分:1
  • C# 只运行一个实例的C#登陆且跳转程序
    C# 只运行一个实例的C#登陆且跳转程序_首先 设置 连接到配置文件组建 App.config,当然 这里的 ConfigurationManager 系统是默认不使用其命名空间的 因此需要解析。连接SQLSERVER数据库后判断数据库密码等。本登录窗口防止多开,只能运行一个实例,多运行会被弹窗提示。
    2022-12-05 17:35:03下载
    积分:1
  • bolieda
    说明:  一个模拟雷达杂波的程序代码,对开发雷达模拟方面有借鉴作用。(A simulated radar clutter the code, the development of radar simulation serve as a reference.)
    2011-04-09 21:14:29下载
    积分:1
  • demo44b0TcpSvr
    ADS1.2 S3C44B0 TCP/IP TCP SERVER CODE
    2012-12-10 14:11:27下载
    积分:1
  • 贪吃蛇
    基于STM32的贪吃蛇小游戏,通过按键控制蛇的方向,外接两个按键。液晶屏显示(Based on STM32 Snake Eating Game, the direction of the snake is controlled by keys, and two keys are attached. LCD Displa)
    2020-06-23 17:00:02下载
    积分:1
  • 高质量C++/C编程指南
    说明:  软件质量是被大多数程序员挂在嘴上而不是放在心上的东西! 除了完全外行和真正的编程高手外,初读本书,你最先的感受将是惊慌:“哇!我以前捏造的C++/C程序怎么会有那么多的毛病?” 别难过,作者只不过比你早几年、多几次惊慌而已。 请花一两个小时认真阅读这本百页经书,你将会获益匪浅,这是前面N-1个读者的建议。(Software quality is the majority of programmers have paid lip service rather than the heart! In addition to being a complete layman and a real master of programming, your first reading of the book will be a panic: "Wow! How can I have so many problems with the C++/C program I've made up before?" Don't be sad, the author is only a few years and a few times earlier than you panic. Please spend one or two hours reading this 100 pages of Scripture carefully, and you will benefit a lot from it. This is a suggestion from the previous N-1 readers.)
    2017-06-13 15:49:09下载
    积分:1
  • OCX测试代码
    OCX 的实例项目!OCX 的实例项目!OCX 的实例项目!OCX 的实例项目!OCX 的实例项目!OCX 的实例项目!OCX 的实例项目!OCX 的实例项目!OCX 的实例项目!
    2022-01-26 07:00:42下载
    积分:1
  • Si4730
    说明:  Si4730收音机基于STM32F103,通过按键和LCD7565屏自动搜台和手动搜台(The Si4730 radio is based on STM32F103. It searches the platform automatically and manually by keys and LCD7565 screen.)
    2019-06-29 14:45:02下载
    积分:1
  • 696518资源总数
  • 106174会员总数
  • 31今日下载