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经典游戏BATTLE CITY的C++ BUILDER实现，没有采用DIRECT X技术，使得理解更为容易...
经典游戏BATTLE CITY的C++ BUILDER实现，没有采用DIRECT X技术，使得理解更为容易-classic games BATTLE CITY BUILDER C achieved, not used DIRECT X technology, making it easier to understand
- 2022-03-21 07:48:58下载
- 积分：1
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用于网络传输时的Jpg和Bmp格式相互转换的API封装
用于网络传输时的Jpg和Bmp格式相互转换的API封装-for network transmission of Broadband and PDF format conversion API Packaging
- 2022-10-22 05:15:03下载
- 积分：1
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贪吃蛇游戏源程序,可在VC++中运行,欢迎使用
贪吃蛇游戏源程序,可在VC++中运行,欢迎使用-Snake game source, the VC operation, welcomed the use of
- 2023-04-05 07:15:03下载
- 积分：1
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这是一个用vb＋SQL Server数据库编写的样品检验代码。包括样品的购买库存以及检验的各项程序，是一个很好的vb数据库参考代码...
这是一个用vb＋SQL Server数据库编写的样品检验代码。包括样品的购买库存以及检验的各项程序，是一个很好的vb数据库参考代码-with vb+ SQL Server database prepared by the test sample code. The samples include the purchase of inventory and inspection procedures, is a good reference source database vb
- 2023-04-15 07:10:04下载
- 积分：1
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对于游戏的变化，内存数据的分析，属性数据的变化，。
游戏修改器，对内存数据进行分析，得到变化的属性数据，对属性数据进行修改。-changes for the game, the memory data analysis, changes in the attribute data, attribute data to make revisions.
- 2022-12-06 05:00:03下载
- 积分：1
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prolog it easy program called piskvorky X O X O X O
prolog it easy program called piskvorky X O X O X O
- 2022-07-25 12:07:24下载
- 积分：1
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有关FLASH的介绍,其中有寄存器的设置,以及相关存储器的读写操作...
有关FLASH的介绍,其中有寄存器的设置,以及相关存储器的读写操作-On the introduction of FLASH, which have register settings, as well as associated memory to read and write operation
- 2022-04-10 07:31:30下载
- 积分：1
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various gates model of Verilog HDL description
各种门电路模型的VerilogHDL描述-various gates model of Verilog HDL description
- 2022-03-10 06:50:38下载
- 积分：1
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航空影像的空间后方交会程序,用共线方程,已知地面控制点的情况下,解求像点坐标matlab完成矩阵运算，程序简洁实用...
航空影像的空间后方交会程序,用共线方程,已知地面控制点的情况下,解求像点坐标matlab完成矩阵运算，程序简洁实用-Aerial Images of the space resection procedure, with a total line equation, known ground control points of the case, the solution coordinates matlab order to complete the image point matrix operations, the program simple and practical
- 2022-07-18 10:21:01下载
- 积分：1
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问题描述:
一杯沸水冷却，圆柱体模型，底面半径0.05m，高0.1m，周围温度20度，初始水温100度
方程是四维输运方程（常数a^2=k/(c*...
问题描述:
一杯沸水冷却，圆柱体模型，底面半径0.05m，高0.1m，周围温度20度，初始水温100度
方程是四维输运方程（常数a^2=k/(c*p)，k是热传导系数0.6006焦/（米*秒*度））
初始条件：t=0时水等于100度
边界条件：1.上下壁都是自由冷却，第三类边界条件，周围温度保持在20度（H=k/h,h取1）
2.杯壁绝热，第二类边界条件
图形显示格式,取过圆柱轴的截面温度变化将其做成动画.
-Problem description : a cup of boiling water cooling cylinder model, the bottom radius of 0.05m, 0.1m high. temperature around 20 degrees, initial temperature of 100 degrees equation is four-dimensional equations (a constant ^ 2 = k/(c* p), k is the thermal conductivity coefficient of 0.6006 Coke/(m** seconds degrees)) initial conditions : t = 0 to 100 degree water boundary conditions : 1. upper and lower walls are free cooling, the third boundary conditions, maintain the temperature around 20 degrees (H = k/h, h for 1) 2. Beibi insulation, The second category boundary conditions graphics format, cylindrical shaft for the cross section of its temperature changes caused animation.
- 2022-05-12 17:55:03下载
- 积分：1
