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PC Win32 Timer
一个适用于Windows的计时器应用程序,您可以在其中启动和停止向上/向下计数计时器。计数器在屏幕上显示大字符,允许从大约15英尺的距离读取。
- 2022-03-01 08:41:13下载
- 积分:1
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输入年/月/日,计算得出该日的星期数
输入年/月/日,计算得出该日的星期数 -importation year/month/day, calculated the date of the few weeks
- 2022-10-18 05:30:02下载
- 积分:1
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tsp recursive program (Java)
tsp递归程序实现(Java)-tsp recursive program (Java)
- 2022-02-05 16:04:47下载
- 积分:1
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Microsoft mci interface, the use of MFC utility to set up working into vc++ to r...
使用微软mci接口,利用MFC工具建立的vc++工成,实现了语音朗读和语音识别功能-Microsoft mci interface, the use of MFC utility to set up working into vc++ to realize voice and speech recognition capabilities to read
- 2022-03-14 07:51:09下载
- 积分:1
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实现ping命令的源代码
本程序用于实现客户端ping命令的实现,在其基础上,可以灵活的根据需求修改代码,来实现网线是否正常(ping 网关),判断能否上网(ping 114.114.114.114)等功能。
- 2022-09-03 07:45:03下载
- 积分:1
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This procedure is a file compression, after compression format*. gz. This proced...
本程序是对文件进行压缩,压缩之后的格式为*.gz。本程序只是为了说明压缩和解压的原理,写得比较简明。运行此程序的时候,首先会生成一个.txt文件,然后对该文件进行压缩,生成.gz文件,最后会对.gz文件进行解压,生成一个新的.txt文件。-This procedure is a file compression, after compression format*. gz. This procedure only in order to explain the principles of compression and decompression, written in more concise. Run this program, the first will generate a. Txt file, and then compress the file to generate. Gz files, last will. Gz unzip files to generate a new. Txt file.
- 2022-09-30 04:50:03下载
- 积分:1
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TCL语言学习的几个小程序,非常简单,学习tcl的例子。
TCL语言学习的几个小程序,非常简单,学习tcl的例子。-TCL language learning process several small, very simple, learning peers example.
- 2022-03-23 13:50:51下载
- 积分:1
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这是世界
这是世界编程大赛一等奖的作品,把着段代码复制下来存为文本文档,命名为1
在DOS下用debug
- 2022-08-08 21:26:44下载
- 积分:1
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这是用C++编的用链表求大数阶乘,
这是用C++编的用链表求大数阶乘,-This the C series for the use of large numbers factorial chain,
- 2022-03-07 12:50:11下载
- 积分:1
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以深度为k的满二叉树(n=2k
以深度为k的满二叉树(n=2k-1)为例,假设表中每个记录的查找概率相等,即 pi=1/n(1≤i≤n),而树的第i层上有2i-1个结点,因此,折半查找的平均查找长度为:
所以,折半查找的平均时间复杂度为O(log2n)。
-To a depth of k over the binary tree (n = 2k-1) as an example, suppose the table to find the probability of each record the same, that is, pi = 1/n (1 ≤ i ≤ n), and the tree layer of the first i There are 2i-1 nodes, therefore, to find half the average length of search as follows: Therefore, to find half the average time complexity is O (log2n).
- 2023-08-09 03:30:03下载
- 积分:1