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一个在控制台下打印日历的源码,只要输入年和月,就能打印当月的日历,包括星期...
一个在控制台下打印日历的源码,只要输入年和月,就能打印当月的日历,包括星期-Print a calendar in the console under the source, as long as the input and on, you can print the calendar month, including the week
- 2022-05-12 10:55:14下载
- 积分:1
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井字游戏
井字游戏函数返回游戏状态1游戏结束的结果1比赛过程中游戏结束,没有结果函数绘制的井字游戏玩家标记板
- 2022-02-03 00:15:28下载
- 积分:1
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一个控制台下的验证哥德巴赫猜想的程序源码,我们当时课上的作业...
一个控制台下的验证哥德巴赫猜想的程序源码,我们当时课上的作业-Under a single console to verify the procedures Goldbach Conjecture source, and we had classes on operating
- 2022-08-19 10:18:38下载
- 积分:1
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一个完整的程序,以平滑的图像在不同的尺度。它包括所有必要的…
A complete program to smooth an image on different scales. It include all necessary binary codes *.c and also headers *.h-A complete program to smooth an image on different scales. It include all necessary binary codes*.c and also headers*.h
- 2022-02-22 07:57:55下载
- 积分:1
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A program shows how to implement the Huffman code contains encoding and decodi...
这是一个有关哈夫曼编码的软件,包括哈夫曼的编码和翻译.-A program shows how to implement the Huffman code contains encoding and decoding
- 2022-02-15 00:55:31下载
- 积分:1
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先输入图的各顶点名,再输入图的邻接矩阵从而建立图,并用笛施卡尔,普里姆等三种方法求其最小生成树,...
先输入图的各顶点名,再输入图的邻接矩阵从而建立图,并用笛施卡尔,普里姆等三种方法求其最小生成树,-input vertices of the plan, and plans to import the adjacency matrix thereby establishing map, and use flute Shi Carl prim other three methods for the minimum spanning tree,
- 2022-06-16 23:23:37下载
- 积分:1
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C++编写的控制台上的电话簿管理系统
C++编写的控制台上的电话簿管理系统-telephone note management in console by c++
- 2022-05-14 09:21:53下载
- 积分:1
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一个0
一个0-1背包问题的C++实现,背包的容量为t,各物品的重量分别为w1,w2。。。wn,找一个能装下最大重量的物品组合,用递归形式的贪心法实现-a 0-1 knapsack problem of C achieved, the capacity for backpack t, the weight of the items were w1, w2. . . Wn, one can find the largest installed under the weight of goods portfolio, using recursive form greedy Method
- 2022-05-28 10:59:03下载
- 积分:1
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汽车的java应用程序实例的JavaBean JavaBean通用模板。这个...
auto JAVA程序实际应用JAVABean的实例,通用的JAVABean模板。在此与大家分享。-auto JAVA application procedures JAVABean example JAVABean generic template. The share with you.
- 2022-03-16 17:41:44下载
- 积分:1
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多项式加法尔,Pa Pa = Pb,利用两个多项式和多项式与节点"…
实现多项式加法,Pa=Pa+Pb,利用两个多项式的节点构成“和多项式”-polynomial Ghaffar, Pa Pa = Pb, using two polynomials node "and polynomial"
- 2022-05-12 23:06:57下载
- 积分:1