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#include <mega8.h>
#include <stdio.h>
#include <delay.h>...
#include
#include
#include
#include
#include
#include
#define TG PORTB.1
#define RF_Rx PIND.2
#define Busy PIND.3
#define Mess1 PORTB.0
#define Mess2 PORTD.7
#define Mess3 PORTD.6
#define Mess4 PORTD.5
#define Mess5 PORTB.7
#define Mess6 PORTB.6
#define Buzzer PORTD.0
#define Zone1 PINC.0
#define Zone2 PINC.1
#define Zone3 PINC.2
#define Zone4 PINC.3
#define Zone5 PINC.4
#define Zone6 PINC.5
#define Zone7 PIND.1
-#include
#include
#include
#include
#include
#include
#define TG PORTB.1
#define RF_Rx PIND.2
#define Busy PIND.3
#define Mess1 PORTB.0
#define Mess2 PORTD.7
#define Mess3 PORTD.6
#define Mess4 PORTD.5
#define Mess5 PORTB.7
#define Mess6 PORTB.6
#define Buzzer PORTD.0
#define
- 2022-03-15 02:53:31下载
- 积分：1
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数据压缩教程+源码
数据压缩教程+源码-source data compression Guide
- 2023-01-25 00:00:04下载
- 积分：1
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0_1背包问题使用一个给定n种去的动态规划解法…
0_1背包问题用动态规划解给定n种物品和一背包。物品i的重量是wi，其价值为vi，背包的容量为c。问应如何选择装入背包中的物品，使得装入背包中物品的总价值最大？
在选择装入背包的物品时，对每种物品i只有两种选择，即装入背包或不装入背包。不能将物品i装入背包多次，也不能只装入部分的物品i。因此，该问题称为0-1背包问题。-0_1 knapsack problem using dynamic programming solution of a given n types of goods and one backpack. Item i is the weight of wi, the value for vi, knapsack capacity c. Question should be how to choose the items into the backpack, the backpack into the total value of the largest items? In the selection of the items into the backpack, for each of the items i have only two choices, that is loaded or not loaded backpack backpack. Items should not be many times i load backpack can not only part of the goods loaded i. Therefore, the problem known as the 0-1 knapsack problem.
- 2023-04-12 03:25:02下载
- 积分：1
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这是基于4*4键盘，及液晶的菜单设计，菜单内容包括波形、峰峰值和频率。...
这是基于4*4键盘，及液晶的菜单设计，菜单内容包括波形、峰峰值和频率。-This is based on the 4* 4 keyboard, and LCD menu design, menu content, including waveform, peak-to-peak and frequency.
- 2023-07-27 19:30:03下载
- 积分：1
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huffman编码 hao a
huffman编码 hao a -Huffman coding a hao
- 2022-04-11 18:25:40下载
- 积分：1
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是一个压缩解压缩的标准代码,简单明了, 易用易懂
是一个压缩解压缩的标准代码,简单明了, 易用易懂-Is a compression standard decompression code, simple and clear, easy-to-use easy-to-understand
- 2022-04-13 12:30:33下载
- 积分：1
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源代码可能是错误的。转载，罗兰05:34
源代码，可能会有错误。是转载的，呵呵 不好意思-source code may be wrong. Is reproduced, Loren 05:34
- 2022-06-12 08:24:11下载
- 积分：1
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- 2023-02-13 08:25:03下载
- 积分：1
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自适应算术编码。这个项目假设读者已经了解基本的算术压缩编码的概念。...
自适应算术编码。这个项目假设读者已经了解基本的算术压缩编码的概念。-adaptive arithmetic coding. The project has been the assumption that readers understand basic arithmetic coding concept.
- 2022-03-03 05:26:06下载
- 积分：1
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开发环境是CCS，在DM642平台上实现H.263编解码
开发环境是CCS，在DM642平台上实现H.263编解码-CCS is a development environment in DM642 platform to achieve H.263 codec
- 2022-02-02 20:26:10下载
- 积分：1
