-
uart 块核心
uart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreuart 块 coreu
- 2023-01-14 08:25:03下载
- 积分:1
-
Data structure course first experiment requirements: 1. Base class and derived c...
数据结构课程第一次实验
要求:1.基类和派生类的定义和实现(.h .cpp)
2.+ 运算符重载
3.
- 2023-07-18 00:15:02下载
- 积分:1
-
triallkfjnklgnjfkljngfklnjlkfnflkfg
- 2023-08-19 20:55:03下载
- 积分:1
-
备份数据库(c#+mssql) 注意: Server2000必须安装补丁3,数据库文件备份在 XX:Program FilesMicrosoft SQL Ser...
备份数据库(c#+mssql) 注意: Server2000必须安装补丁3,数据库文件备份在 XX:Program FilesMicrosoft SQL ServerMSSQLBACKUP-backup database (# mssql c) Note : Server2000 three patches to be installed, the database backup file XX : Program Files Microsoft SQL Server MSSQL Backup
- 2022-07-25 22:52:12下载
- 积分:1
-
利用哈夫曼编码构造的完整的编/译码系统,包括初始化、编码、译码、显示等,并将其输出在文件中。...
利用哈夫曼编码构造的完整的编/译码系统,包括初始化、编码、译码、显示等,并将其输出在文件中。-The use of Huffman encoding the complete structure of the encoder/decoder system, including the initialization, encoding, decoding, display and output in the document.
- 2022-01-22 17:55:18下载
- 积分:1
-
停车场的程序,是用多线程写的,有详细的注释
停车场的程序,是用多线程写的,有详细的注释-parking procedures is the use of multi-threaded writing, a detailed Notes
- 2022-01-24 16:23:08下载
- 积分:1
-
在一个圆形操场的四周摆放着n堆石子。现要将石子有次序地合并成一堆。规定每次只能选相邻的两堆石子合并成新的一堆,并将新的一堆石子数记为该次合并的得分。试设计一个算...
在一个圆形操场的四周摆放着n堆石子。现要将石子有次序地合并成一堆。规定每次只能选相邻的两堆石子合并成新的一堆,并将新的一堆石子数记为该次合并的得分。试设计一个算法,计算出将n堆石子合并成一堆的最小得分和最大得分,并分析算法的计算复杂度。-in a circle around the playground are placed n gravel pile. Is a stone should order to be merged into a heap. Stipulated that only elected adjacent to the pile of gravel into the new heap, and a new pile of gravel credited for the combined scores. Design a test algorithm to calculate n heap into a pile of gravel to the minimum score and the biggest score and analysis of algorithm complexity.
- 2022-03-22 21:40:18下载
- 积分:1
-
这个项目简洁、通俗地解释了有关平衡二叉树的问题。也提供了源代码和一个供演示的通用类。描述/提供了如何平衡二叉树的功能。...
这个项目简洁、通俗地解释了有关平衡二叉树的问题。也提供了源代码和一个供演示的通用类。描述/提供了如何平衡二叉树的功能。-the project concise and simple explanation of the balanced binary tree problem. Also provided source code and a demonstration for the general category. Description/how to provide balanced binary tree functions.
- 2023-08-10 15:30:03下载
- 积分:1
-
用C语言编写的有关,两个单链表的归并排序操作.
用C语言编写的有关,两个单链表的归并排序操作.-C language of the two single-Chain merge sorting operation.
- 2023-05-04 15:05:03下载
- 积分:1
-
根据图书管理的功能要求,结合学校图书管理的实际情况,系统分成以下若干模块:编目、典藏、流通、读者、查询、系统维护。...
根据图书管理的功能要求,结合学校图书管理的实际情况,系统分成以下若干模块:编目、典藏、流通、读者、查询、系统维护。-According to the functional requirements of library management, combined with the actual situation of the school library management, the system divided into several modules: cataloging, collection, circulation, reader, search, system maintenance.
- 2023-03-06 09:05:03下载
- 积分:1