-
C语言通讯程序库windows版
C语言通讯程序库windows版 -C language communication library windows version of C language communication library windows version of
- 2022-02-11 22:29:21下载
- 积分：1
-
The programme is about control panel.When you click it ,you can get message hand...
有关于控制面板的,当你单击的时候可以看到消息的处理过程-The programme is about control panel.When you click it ,you can get message handling process.
- 2022-03-15 18:55:54下载
- 积分：1
-
a DLL with MFC's date library
一个用MFC DLL开发的日期函数库-a DLL with MFC"s date library
- 2022-04-26 22:20:57下载
- 积分：1
-
本程序利用数据结构中的回溯算法的非递归对以知地图进行全路线查找，可以完成最短路线，最少费用，和所有路线的显示...
本程序利用数据结构中的回溯算法的非递归对以知地图进行全路线查找，可以完成最短路线，最少费用，和所有路线的显示-procedures for the use of the data structure of the back- recursive algorithm right to know what the road map for the entire search, the shortest route to be completed, at least cost, and all the routes show
- 2022-07-28 00:21:11下载
- 积分：1
-
A custom button header files, the button automatically displays the features des...
自定义按钮的头文件，按钮上面自动显示功能描述。可以重载自己的按钮。-A custom button header files, the button automatically displays the features described above. You can override its own button.
- 2023-07-23 05:45:03下载
- 积分：1
-
Pci programming examples
Pci 编程例子-Pci programming examples
- 2022-03-22 08:10:47下载
- 积分：1
-
ulguri is good program source.
ulguri is good program source.
- 2022-02-05 12:46:52下载
- 积分：1
-
Colormatrix for the chemalux coating AR.
Colormatrix for the chemalux coating AR.
- 2022-01-26 04:48:01下载
- 积分：1
-
huffman tree 问题描述：设一份电文中有不同出现频率的字符，为了提高电文的输入和翻译效率，必须有一套简短而又不会产生歧义的字符代码。试根据哈夫曼算法，...
huffman tree 问题描述：设一份电文中有不同出现频率的字符，为了提高电文的输入和翻译效率，必须有一套简短而又不会产生歧义的字符代码。试根据哈夫曼算法，对电文中的不同字符，构造出一棵哈夫曼树，对每个字符进行编码。-Huffman tree Problem description : Let a message different frequency of the characters, in order to enhance the input and message translation efficiency, we must have a brief but no ambiguity of the characters code. Examination under Huffman algorithm, the message of characters, construct a Huffman tree for each character coding.
- 2022-10-09 01:35:04下载
- 积分：1
-
编号为1，2，…,n的n个人按顺时针方向围坐一圈，每人持有一个密码（正整数），一开始人选一个正整数作为报数上限m,从第一个人开始按顺时针方向从自1开始顺序报数，...
编号为1，2，…,n的n个人按顺时针方向围坐一圈，每人持有一个密码（正整数），一开始人选一个正整数作为报数上限m,从第一个人开始按顺时针方向从自1开始顺序报数，报道m时停止报数。报m的人出列，将他的密码作为新的m值，从他的顺时针方向上的下一个人开始重新从1报数，如此下去，直至所有人全部出列为止，设计一个程序求出出列顺序。采用单向循环链表模拟此过程，按照出列的顺序印出各人的编号测试数据：m的初值为20；n=7,7个人的密码依次为：3，1，7，2，4，8，4，首先m的值为6（正确的出列顺序应为6,1,4,7,2,3,5）-No. 1, 2, ..., n n clockwise direction by individuals sitting around a circle, each holding a password (positive integers), a candidate started as a positive integers m ceiling on the number of reported from the first individuals to embark on the clockwise direction from the start sequence from a few newspaper reports m reportedly stopped a few. M reported out of the list of his password as a new value m, from the clockwise direction on the next re-started from a few reported so on, until all out all out, the design of a procedure sought out the order out. Listless one-cycle simulation process and follow the sequence shown in the numbers printed each test data : m for the initial 20; N = 7,7 personal passwords were : 3,1,7,2,4,8
- 2022-01-24 15:11:40下载
- 积分：1
