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(1)构造文法G的LR(0)项目
(2)构造文法G的LR(0)项目集规范族及识别活前缀的DFA
(3)证明文法G不是LR(0)文法而是SLR(1)文法,...
(1)构造文法G的LR(0)项目
(2)构造文法G的LR(0)项目集规范族及识别活前缀的DFA
(3)证明文法G不是LR(0)文法而是SLR(1)文法,并构造SLR(1)分析表
(4)设计LR语法分析程序,且能输出分析过程
(5)列举两个例子测试语法分析程序(识别失败一例,识别成功一例,后者推导步骤不得少于10步)
-(1) construct grammar G of the LR (0) item (2) construct grammar G of the LR (0) item sets standards and identification of family living prefix DFA (3) prove that the grammar G is not LR (0) grammar, but the SLR (1 ) grammar, and constructs SLR (1) analysis table (4) design LR parser, and can output analysis process (5) cited two examples of parsing test procedures (identification fails an example, identify the success of a case, the latter shall not be derived step Less than 10 steps)
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of the document infile outfile read into output documents, infile outfile to com...
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C编译器,在VC6.0环境下开发,是C的一个简单编译器,但可以运行任何C程序,可以函数嵌套...
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