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java.net库的C++实现。方面C++程序员编写网络程序,更方面JAVA to C++程序员。...
java.net库的C++实现。方面C++程序员编写网络程序,更方面JAVA to C++程序员。-java.net library C++ realize. Aspects of C++ Programmers procedures to prepare the network, but also aspects of JAVA to C++ Programmers.
- 2023-08-25 07:15:03下载
- 积分:1
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a UDP Multicast (multicast) example
一个UDP多播(组播)示例-a UDP Multicast (multicast) example
- 2023-04-23 07:25:03下载
- 积分:1
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opal
opal-3.2.2-src.zip配合使用ptlib-2.2.2-src.zip 源码2.2.2 版本-opal-3.2.2-src.zip use ptlib-2.2.2-src.zip source version 2.2.2
- 2022-01-26 20:15:47下载
- 积分:1
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this article for the BCB after the developers, not only to FlashGet software dev...
这篇文章后对于BCB开发人员来说,不仅可以对 FlashGet 等软件的开发原理有一定的了解,特别是在开发组件方面也有很大的指导作用,请耐心的将它看完。很简单-this article for the BCB after the developers, not only to FlashGet software development tenets of a certain understanding, especially in the development of components are also great role in guiding, patient reading it. Very simple! !
- 2022-03-24 23:20:26下载
- 积分:1
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在局域网网中,客户端通过向服务器端发送连接请求,可以同服务器端进行网络围棋。...
在局域网网中,客户端通过向服务器端发送连接请求,可以同服务器端进行网络围棋。-in LAN network, the client to the server through this connection request, the same network server Go.
- 2022-11-18 18:55:03下载
- 积分:1
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communications network using socket, a reference value
实现网络通信,采用socket方式,有参考价值-communications network using socket, a reference value
- 2022-02-21 07:14:13下载
- 积分:1
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本人收集的一个windwos下的端口扫描程序源代码.
本人收集的一个windwos下的端口扫描程序源代码.-I collected a windwos the port scanning source code.
- 2023-04-04 11:45:03下载
- 积分:1
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这是一个应用Socket做的简单聊天室程
这是一个应用Socket做的简单聊天室程-Socket This is an application process to do simple chat room
- 2022-03-30 23:45:48下载
- 积分:1
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unsustainable under the agreement, users send frames, will first interception Ch...
非持续CSMA
该协议下,用户在发送帧之前,会先侦听信道的状况,如果没有其他站点发送,它就发送。若信道忙,它就等待一个随机的时间后重复以上动作。
对于某一帧而言,信道是否忙,即是看其绝对时间(FRAMETIME*i+dt)的前一帧时内(FRAMETIME*(i-1)+dt ~ FRAMETIME*i+dt)是否存在发送帧。若无则发送,有则等待一随机时间。
-unsustainable under the agreement, users send frames, will first interception Channel situation, if no other site sent, it sent. If Channel busy, it would wait for a random time to repeat the action. For a frame, whether the busy channel, that is, look at his absolute time (FRAMETIME* i dt) of a time (FRAMETIME* (i-1) dt ~ FRAMETIME dt* i) the existence of this frame. If not then this, then wait for a random time.
- 2022-03-16 02:26:57下载
- 积分:1
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一个用Sockets实现的简单通信:首先运行ASCIIServer.java再运行ASCIIClient.java。然后客户端会发送65...
一个用Sockets实现的简单通信:首先运行ASCIIServer.java再运行ASCIIClient.java。然后客户端会发送65-90到服务端,并在服务端翻译为ASCII码。-A simple implementation using Sockets communication: First run ASCIIServer.java run ASCIIClient.java. And the client will be sent to the service side 65-90, and Translations Service client for ASCII code.
- 2022-08-11 10:17:36下载
- 积分:1