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md5 encrypted C This is a class which encapsulates a set
md5加密程序 C++ This a class which encapsulates a set-md5 encrypted C This is a class which encapsulates a set
- 2023-07-11 06:25:02下载
- 积分：1
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Base64 encoding and decoding, MD5 encryption source DEMO
Base64编码与解码，MD5加密源码 DEMO-Base64 encoding and decoding, MD5 encryption source DEMO
- 2023-04-04 00:25:03下载
- 积分：1
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MD5Win
MD5Win-MD5文本密码生成-MD5Win-MD5 text password generation
- 2022-07-28 13:25:00下载
- 积分：1
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基于JAVA语言的MD5编程，可以进行实验讲解，有输入输出示范
基于JAVA语言的MD5编程，可以进行实验讲解，有输入输出示范-based on MD5 Java programming language, can conduct experiments to explain, input-output model
- 2022-10-24 10:55:03下载
- 积分：1
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对于这个问题的实现、刚刚给过一个程序，突然想起另外一种简单一些的方法，一并给出[笔者长期从事移动通信系统的无线链路调制与解调、物理层实现方面的工作。在移动通信G...
对于这个问题的实现、刚刚给过一个程序，突然想起另外一种简单一些的方法，一并给出[笔者长期从事移动通信系统的无线链路调制与解调、物理层实现方面的工作。在移动通信GSM系统中，我们进行语音或者业务信道解调时，都会遇到CRC的求解。通常在硬件DSP实现时，特别是40位CRC求解时候，由于生成多项式有41项，DSP最大一次能处理40位，所以使用单个寄存器会遇到一些困难，那么以下这个程序将会解决这一困难（这是针对定点DSP、C55xx的编程实现方法）。]：
-For the realization of this issue, just to have a program, suddenly reminded of another simpler way to be given [the author has long been engaged in mobile communication system modulation and demodulation of wireless links, the physical layer to achieve work. GSM in the mobile communications system, we have a voice or channel demodulation operations, it will encounter the solution of CRC. DSP hardware usually realize, especially when solving the 40 CRC, as the generation polynomial has 41, DSP can handle the largest 40, so using a single register may encounter some difficulties, then following this process will solve this One difficulty (which is for fixed-point DSP, C55xx realize programming methods). ]:
- 2022-03-14 13:54:53下载
- 积分：1
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JAVA密码保护页面,可以保护你不让想看的人，设置简单
JAVA密码保护页面,可以保护你不让想看的人，设置简单-JAVA password-protected pages, and can protect you from those who want to set up a simple
- 2023-07-31 21:45:03下载
- 积分：1
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采用高级加密标准aes算法针对流媒体加密程序
采用高级加密标准aes算法针对流媒体加密程序-Using the Advanced Encryption Standard algorithm aes encryption for streaming media
- 2022-03-24 20:40:00下载
- 积分：1
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cox方法展频水印matlab源码，对bitmap图像隐藏信息
介绍利用AFEPack求解自适应有限元的基本使用方法. 其输入参数为利用easymesh对区域进行剖分后的得到的文件.-AFEPack introduce the use of adaptive finite element to solve the basic usage. Its input parameters for the use of easymesh region after the partition of documents.
- 2022-05-22 22:29:13下载
- 积分：1
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Rjindeal加密算法
Rjindeal加密算法-Rjindeal encryption algorithm
- 2023-03-26 06:00:03下载
- 积分：1
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rsa实验,刚学会的
rsa实验,刚学会的-rsa experiments, the newly acquired
- 2022-02-01 18:31:21下载
- 积分：1
