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表达式求值是程序设计语言编译中的一个最基本问题，它的实现是栈的应用的典型例子。...
表达式求值是程序设计语言编译中的一个最基本问题，它的实现是栈的应用的典型例子。-Expression evaluation is a programming language compiler in a fundamental question, and its implementation is a typical example of the application stack.
- 2022-01-22 04:05:49下载
- 积分：1
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一个带界面的在线测试系统，从数据库中随意抽题，在线回答，并且反馈答案。...
一个带界面的在线测试系统，从数据库中随意抽题，在线回答，并且反馈答案。-An interface with the online testing system, arbitrarily drawn from the database title, on-line to answer, and the feedback answer.
- 2023-03-08 07:50:04下载
- 积分：1
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三层数据库考试系统，很不错的，大家可以看看。
三层数据库考试系统，很不错的，大家可以看看。-Three-tier examination system database, it is good, we will look at.
- 2023-03-25 20:40:03下载
- 积分：1
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如何将“所有”添加到列表框或组合框中。
SELECT "*" AS RecID, "(All)" AS Employee
FROM Employees AS T1
UNION
SELECT T1.EmployeeID AS RecID, [FirstName] & " " & [LastName] AS Employee
FROM Employees AS T1
ORDER BY Employee;
- 2022-07-11 06:24:58下载
- 积分：1
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计算机模拟考试3级网络技术笔试
计算机模拟考试3级网络技术笔试-computer mock examinations three network technology quiz
- 2022-05-07 05:55:16下载
- 积分：1
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约瑟夫问题有原始的约瑟夫和发展了的约瑟夫两种。 原始的约瑟夫的描述： 古代某法官要判决N个犯人的死刑，他有一条荒唐的法律，将犯人站成一个圆圈，从第S个人开始数起...
约瑟夫问题有原始的约瑟夫和发展了的约瑟夫两种。 原始的约瑟夫的描述： 古代某法官要判决N个犯人的死刑，他有一条荒唐的法律，将犯人站成一个圆圈，从第S个人开始数起，每数到第D个犯人，就拉出来处决，然后再数D个，数到的人再处决―――直到剩下的最后一个可赦免。 发展的约瑟夫的描述： 古代某法官要判决N个犯人的死刑，但这N个人每人持有一个密码，他有一条荒唐的法律，将犯人站成一个圆圈，法官先给出一个密码M，从第S个人开始数起，每数到第M个犯人，就拉出来处决，再根据这个人所持有的密码F，然后再数F个，数到的人再处决，以此类推―――直到剩下的最后一个可赦免。-Joseph problems have original development of the Joseph and Joseph two. The original Joseph Description : Ancient a judge to sentence N inmates of the death penalty, he is a ridiculous law, prisoners station into a circle, from S began a few individuals, every few months to D prisoners, pull out executions, then D, the number of people to be re-executed--- until the last one left to be pardoned. The development of the Joseph Description : Ancient a judge to sentence N inmates of the death penalty, but each individual N holders a password, he is a ridiculous law, prisoners station into a circle, the judges first gave a password M, S individuals from the beginning of several, each of the first few inmates M , pull hi
- 2022-03-11 16:54:39下载
- 积分：1
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清华大学数据结构c++版的代码，很稀罕，很稀有，相当的珍贵...
清华大学数据结构c++版的代码，很稀罕，很稀有，相当的珍贵-Tsinghua University, the data structure c++ version of the code, very rare, very rare, very valuable
- 2023-05-16 05:30:03下载
- 积分：1
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1, for providing patients with better and faster and more efficient services and...
1、为病人提供更好更快、更快的服务，提高医院在医疗市场的竞争力以及吸引更多的病人到本医院就医；
2、人力工资昂贵，迫使医院采用计算机以提高劳动效率；
功能：1、门诊挂号：为病人提供就医卡方便病人；
2、住院病人管理系统：是医院可以随时了解病人情况；
3、药房管理系统：提高了药品管理的质量，和工作效率；
4、门诊医生工作站、住院费用的管理、病历管理系统、以及外部接口等。-1, for providing patients with better and faster and more efficient services and improve the hospital in the medical market competitiveness and to attract more patients to the hospital 2, manpower, high cost of labor, forcing hospitals to improve the working efficiency of the computer function : 1, out-patient registration: In order to provide patients with the convenience of patients for medical treatment card 2, patients management system: a hospital patient can understand 3, pharmacy management system: To improve the quality of drug management, and efficiency 4, the doctor-patient workstations, the cost of hospital management, medical records management system, as well as external interfaces.
- 2023-05-18 04:40:04下载
- 积分：1
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sysbase 12 用程序实现加卸载数据。
sysbase 12 用程序实现加卸载数据。
- 2023-01-19 11:25:03下载
- 积分：1
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链式结构堆栈类的类模板实现及用堆栈类求解N皇后问题
链式结构堆栈类的类模板实现及用堆栈类求解N皇后问题-chain structure of the stack type and class template stack used for solving problems N Queen
- 2022-03-02 18:41:52下载
- 积分：1
