-
详细的XML实例基于libxml2钻使用,联合应用的介绍…
详细演练 xml 基于 libxml2 的范例使用,并结合应用呈现-Detailed drill xml examples based on libxml2 use, and combined application presented
- 2022-01-22 05:36:32下载
- 积分:1
-
linux 下的人脸识别代码,编译的时候需要配置好IDE
linux 下的人脸识别代码,编译的时候需要配置好IDE-face detection
- 2022-04-19 03:52:59下载
- 积分:1
-
一周内学会linux系统管理PPT文档。第一讲Linux的概述.ppt第十六讲NFS服务.ppt...
一周内学会linux系统管理PPT文档。第一讲Linux的概述.ppt第十六讲NFS服务.ppt-Institute of linux system administration within a week PPT document. First talk about Linux, an overview. Ppt 16th speaking NFS services. Ppt
- 2022-08-05 23:53:18下载
- 积分:1
-
This is a linux based on the PCI bus driver SD card good information, very usefu...
这是一个关于linux下基于PCI总线的SD卡驱动方面的好资料,对驱动开发很有用。-This is a linux based on the PCI bus driver SD card good information, very useful for driver development.
- 2022-02-07 02:01:12下载
- 积分:1
-
linux基本命令,学习指南。适合用于初学者
linux基本命令,学习指南。适合用于初学者-basic commands, study guide. Suitable for beginners
- 2022-03-20 14:39:53下载
- 积分:1
-
LINUX system in the implementation of the algorithm for PV operation, the prepar...
在LINUX系统下实现PV操作的算法,课程设计时编写的,能够成功运行-LINUX system in the implementation of the algorithm for PV operation, the preparation of curriculum design and be able to run successfully
- 2022-01-25 17:13:11下载
- 积分:1
-
支持AMD64的汇编编译器源码
支持AMD64的汇编编译器源码-support AMD64 compiler source code compilation
- 2022-10-14 03:20:03下载
- 积分:1
-
Linux0.11内核源代码 Linux0.11内核源代码
Linux0.11内核源代码 Linux0.11内核源代码-Linux0.11 kernel source code Linux0.11 kernel source code
- 2023-07-19 14:20:03下载
- 积分:1
-
GtkWidget*window
gtk_init (&argc, &argv)...
GtkWidget *window
gtk_init (&argc, &argv)
window = gtk_window_new (GTK_WINDOW_TOPLEVEL)
gtk_widget_show (window)
gtk_main ()
return(0) - GtkWidget*window
gtk_init (&argc, &argv)
window = gtk_window_new (GTK_WINDOW_TOPLEVEL)
gtk_widget_show (window)
gtk_main ()
return(0)
- 2023-02-06 20:55:03下载
- 积分:1
-
Well
著名图论问题之一。邮递员从邮局出发送信,要求对辖区内每条街,都至少通过一次,再回邮局。在此条件下,怎样选择一条最短路线?此问题由中国数学家管梅谷于1960年首先研究并给出算法,故名。-Well-known graph theory problems. Postman deliver a letter from the post office proceed to require every street within the right area, at least through the time, return to post office. Under these conditions, how to select a shortest route? This issue by the Chinese mathematician Mei Gu tube study in 1960, and gives the first algorithm, hence the name.
- 2022-06-18 09:20:13下载
- 积分:1