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ARM微处理器为核心 进行军用高性能PDA设计ARM微处理器为核心 进行军用高性能PDA设计...
ARM微处理器为核心 进行军用高性能PDA设计ARM微处理器为核心 进行军用高性能PDA设计-ARM microprocessor core of the military for high-performance PDA design of the ARM microprocessor core for military High-performance PDA Design
- 2022-02-09 22:07:35下载
- 积分：1
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VHDL的数字设计与综合的经典图书，与大家共享
VHDL的数字设计与综合的经典图书，与大家共享-VHDL digital design and synthesis of the classic books, and share
- 2022-03-20 12:36:14下载
- 积分：1
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实例24
实例24-HTTP服务器 实例24-HTTP服务器-24-HTTP server examples 24-HTTP server
- 2023-09-01 07:45:03下载
- 积分：1
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软件质量是由大多数程序员的头脑和不只是吨。
软件质量是被大多数程序员挂在嘴上而不是放在心上的东西！
除了完全外行和真正的编程高手外，初读本书，你最先的感受将是惊慌：“哇！我以前捏造的C++/C程序怎么会有那么多的毛病？”
别难过，作者只不过比你早几年、多几次惊慌而已。
请花一两个小时认真阅读这本百页经书，你将会获益匪浅，这是前面N-1个读者的建议
-software quality is linked by the majority of programmers in mind and not just the things! In addition to completely out of the loop and genuine master of programming, early Reader book, you will be the first to the feelings of panic : "wow! I used to fabricate the C/C program how did so many of the defects? "Do not sorry The author only a few years than you, it more often panic. Please spend 12 hours reading this book by 100, you will be benefited, which is in front of N-a suggestion of the readers
- 2022-03-18 03:13:20下载
- 积分：1
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Java技术教程.基础篇书中的源代码，共有17章。
Java技术教程.基础篇书中的源代码，共有17章。-Java technology tutorials. The basis of the source code of the book chapter, a total of 17 chapters.
- 2023-02-20 10:30:05下载
- 积分：1
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用VC++编写USB接口通信程序的书籍，实用性强
用VC++编写USB接口通信程序的书籍，实用性强-prepared with VC USB Communication Program of books, practical
- 2022-03-20 20:06:43下载
- 积分：1
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犯错
java3
- 2022-05-08 09:52:34下载
- 积分：1
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用堆栈实现迷宫求解问题
基本思想:
若当前位置可以通过,则压入栈中,否则探求下一位置,若走不通,则回朔,迷宫大小:M*N.迷宫设置自定义。
求解迷宫...
用堆栈实现迷宫求解问题
基本思想:
若当前位置可以通过,则压入栈中,否则探求下一位置,若走不通,则回朔,迷宫大小:M*N.迷宫设置自定义。
求解迷宫问题的简单方法是：从入口出发，沿某一方向进行探索，若能走通，则继续向前走；否则沿原路返回，换一方向再进行探索，直到所有可能的通路都探索到为止。
为避免走回到已经进入的点（包括已在当前路径上的点和曾经在当前路径上的点），凡是进入过的点都应做上记号。-Maze with the stack to achieve the basic idea for solving the problem: If the current position can be adopted, in pressure, otherwise the next location to explore, if a dead end, then back to New Moon, the size of the maze: M* N. maze set up a custom. A simple maze to solve the problem is: starting from the entrance, along a certain direction to explore, can walk, then continue to move forward otherwise return along the same route, a direction for further exploration, until all possible pathways are exploring to date. In order to avoid going back to have access points (including the current path and current path in the point), all the points should be entered mark.
- 2022-03-21 17:16:01下载
- 积分：1
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program code of LABVIEW 8.20
LABVIEW 8.20程序设计从入门到精通
２－９章 程序源码-program code of LABVIEW 8.20
- 2022-03-10 09:16:44下载
- 积分：1
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A client/server application that implements the game of BINGO. This example broa...
A client/server application that implements the game of BINGO. This example broadcasts information via a multicast socket, builds its GUI with Swing components, uses multiple synchronous threads, and communicates with RMI.
- 2022-10-13 01:10:03下载
- 积分：1
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