-
一个小程序，关于成绩管理的，可自动排序
一个小程序，关于成绩管理的，可自动排序-a small program on performance management, automated sequencing
- 2022-03-23 21:32:38下载
- 积分：1
-
this document describe how davicom ic dm9000 can be programmed and controlled. t...
this document describe how davicom ic dm9000 can be programmed and controlled. this ic can be used in the embedded systems and network lan cards. its is 10/100Mpbs ic.
- 2022-02-01 21:22:59下载
- 积分：1
-
LGDP4512 51 drivers, driver TFT display
LGDP4512 51驱动程序，驱动TFT显示-LGDP4512 51 drivers, driver TFT display
- 2022-06-12 15:48:45下载
- 积分：1
-
a C language prepared by the procedures reversi war, absolutely correct, I own d...
一个用C语言编写的黑白棋对战程序，绝对的正确，我自己调试过的，能成功-a C language prepared by the procedures reversi war, absolutely correct, I own debugging off and success
- 2022-08-25 18:57:07下载
- 积分：1
-
DDP测试版1
/***********************************************************************/
- 2023-02-01 17:05:03下载
- 积分：1
-
罗塞塔C++库是一个C++类和例程，使…
The ROSETTA C++ library is a collection of C++ classes and routines that enable discernibility-based empirical modelling and data mining, developed as part of my dissertation. A brief presentation of the library can be found therein.
- 2022-03-21 04:58:45下载
- 积分：1
-
CIH源代码，编程的牛人看看~
CIH源代码，编程的牛人看看~-CIH source code, the programming people look at the cattle ~
- 2022-10-01 17:15:03下载
- 积分：1
-
解决以下问题：
For solving the following problem:
"There is No Free Lunch"
Time Limit: 1 Second Memory Limit: 32768 KB
One day, CYJJ found an interesting piece of commercial from newspaper: the Cyber-restaurant was offering a kind of "Lunch Special" which was said that one could "buy one get two for free". That is, if you buy one of the dishes on their menu, denoted by di with price pi , you may get the two neighboring dishes di-1 and di+1 for free! If you pick up d1, then you may get d2 and the last one dn for free, and if you choose the last one dn, you may get dn-1 and d1 for free.
However, after investigation CYJJ realized that there was no free lunch at all. The price pi of the i-th dish was actually calculated by adding up twice the cost ci of the dish and half of the costs of the two "free" dishes. Now given all the prices on the menu, you are asked to help CYJJ find the cost of each of the dishes.
- 2022-12-06 21:00:03下载
- 积分：1
-
IEEEuwb信道模型下采用pam调整的超宽带通信仿真程序。
IEEEuwb信道模型下采用pam调整的超宽带通信仿真程序。-simulation program of ultra widebandth communicaiton using pam modulation,the channel model adopt is IEEE uwb channel model.
- 2022-06-02 16:47:47下载
- 积分：1
-
简要介绍一个梁的平面弯曲问题，ansys程序
简要介绍一个梁的平面弯曲问题，ansys程序 -Plane bending of a beam problem, ansys procedures
- 2022-01-31 11:06:12下载
- 积分：1
