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C# USB 发送和接收数据
这是一个C# USB 发送和接收数据,可以用于调试USB接口程序
- 2022-03-16 10:57:14下载
- 积分:1
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还没有注册,请先注册。源码要求为至少5个C或Java源码,质量越高得到的下载个数越多(一般为200:上载5个,可以下载200个)。
请不要重复上载同一源码
还没有注册,请先注册。源码要求为至少5个C或Java源码,质量越高得到的下载个数越多(一般为200:上载5个,可以下载200个)。
请不要重复上载同一源码, 站长审核合格后才能开通帐号。如果不想上载源码,可以成为【VIP会员】获得帐号
如果其他会员下载一次您上载的源码,您的可用下载数就会增加1次。更多说明请参看[帮助说明]
-Have not yet registered, please register. Source requirements for at least 5 C or Java source code, the higher the quality of the download to be more the number of (normally 200: 5 uploaded, you can download 200). Please do not repeat the same source upload, station after passing the examination in order to open account. If you do not want to upload source code, you can become a VIP Member] [access to account if the other members to download once you upload the source code, you will increase the number of available download 1 times. More description see [Help]
- 2022-12-23 07:55:03下载
- 积分:1
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您是否考察了众多的在线文档处理控件,而对他们的表现并不十分满意,或者您
已集成了此类产品,尽管不满意,也没有更好的选择?现在您不用再失望了,
将给您最好...
您是否考察了众多的在线文档处理控件,而对他们的表现并不十分满意,或者您
已集成了此类产品,尽管不满意,也没有更好的选择?现在您不用再失望了,
将给您最好的选择。其中的手写批注方案是目前同类软件中最好的手写批注解决方案,
具有领先的技术优势和最好的用户界面。-you visit a large number of files online processing controls, and their performance is not satisfactory, or if you have integrated such products, though not satisfied, it was no better alternative? Now you do not have to be disappointed, will give you the best option. The handwritten endorsement program similar software is the best solution handwritten endorsement, with leading-edge technology and the best user interface.
- 2022-11-19 17:40:03下载
- 积分:1
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COM串口终端调试程序
COM串口终端调试程序-COM serial terminal debugger
- 2022-05-06 12:52:43下载
- 积分:1
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Visual C++源程序代码第三章源程序,系统篇,
Visual C++源程序代码第三章源程序,系统篇,- Visual C++ source program code in chapter three,system portion
- 2022-03-15 11:15:16下载
- 积分:1
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绘图基本功,比较详细的介绍了一些画图,基本包含所有画图炒作...
绘图基本功,比较详细的介绍了一些画图,基本包含所有画图炒作-Drawing basics, a more detailed introduction to a number of drawing, basic drawing contains all the hype
- 2022-03-12 20:13:09下载
- 积分:1
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AIC bands in accordance with statutory order recursive algorithm procedures in a...
AIC频段按照法定顺序递归算法程序按照顺序递归算法进行了估计,然后利用下面的方程确定残差方差的估计值:从AIC的计算结果类型:找到模型结果中最小的AIC(阶数和参数)是估计模型。源代码:aic2.dsw。结果存储在:数据.txt. 通过输出数据,我们可以看出当k1=5时AIC的最小值。因此,最终确定顺序为5,检查结果为参数为:-1.18394,0.813938,-0.518174,0.348744,-0.116818,1.07998,-0.74386,0.475444,-0.253022,0.122781,以确定最小AIC值:AIC=--8981.58,以5:00为顺序出现。
- 2023-05-08 21:35:03下载
- 积分:1
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C语言编程高级入门,使大家的C语言有所提高
C语言编程高级入门,使大家的C语言有所提高-C language programming advanced beginners, so everyone" s C language has increased
- 2022-09-08 00:40:02下载
- 积分:1
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读写文件,将数据库中的数据读出,然后写在文件中
读写文件,将数据库中的数据读出,然后写在文件中-read and write documents, the database will read out the data and then write in the paper
- 2022-03-21 05:56:42下载
- 积分:1
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a proverb can be used to query the contents of the entries and small procedures,...
一个用来查询成语词条及内容的小程序,利用了字符操作方法.包括源代码和程序.-a proverb can be used to query the contents of the entries and small procedures, the use of the methods of operation of the characters. Including source code and procedures.
- 2022-01-26 01:35:08下载
- 积分:1