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21天精通c语言的宝典,国外著名c语言书籍。
21天精通c语言的宝典,国外著名c语言书籍。-21 days proficient c language, the book famous c language books.
- 2023-08-08 15:10:05下载
- 积分:1
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Thinking in C++
语言:
English
格式:
word
Thinking in C++
语言:
English
格式:
word-Thinking in C language : English formats : word
- 2022-05-27 22:01:51下载
- 积分:1
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本资料是介绍mysql用法的帮助文档,希望对需要的朋友有帮助
本资料是介绍mysql用法的帮助文档,希望对需要的朋友有帮助-This information is to introduce the mysql usage to help document, want to help a friend in need
- 2022-02-02 21:36:38下载
- 积分:1
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Windows系统引擎
消息驱动体系
三种编程方法
基于 C 语言与 SDK 工具
基于 C++语言和 MFC 类库
基于 Visual C...
Windows系统引擎
消息驱动体系
三种编程方法
基于 C 语言与 SDK 工具
基于 C++语言和 MFC 类库
基于 Visual C++ 环境-Windows system message-driven system of the engine three methods are based on C programming language and SDK tools based on the C++ Language and MFC class library based on Visual C++ Environment
- 2023-02-08 12:40:04下载
- 积分:1
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一篇介绍无轨迹kalman filter滤波的ppt文章,很清楚的说明了ukf工作的原理和使用方法...
一篇介绍无轨迹kalman filter滤波的ppt文章,很清楚的说明了ukf工作的原理和使用方法
- 2023-02-10 21:45:04下载
- 积分:1
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仿真习题,一个非常好的仿真习题。可以随便下载,值得一看...
仿真习题,一个非常好的仿真习题。可以随便下载,值得一看-Simulation Exercise, a very good simulation exercises. Can easily download, an eye-catcher
- 2022-05-26 02:00:37下载
- 积分:1
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EMC Test of information Beijing Jiaotong University
EMC测试方面的资料北京交通大学--沙斐编写的-EMC Test of information Beijing Jiaotong University- Shafi
- 2022-08-17 12:21:18下载
- 积分:1
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usb2.0中文说明,结合s3c2410芯片,详细介绍了有关寄存器和配置,接口端点等...
usb2.0中文说明,结合s3c2410芯片,详细介绍了有关寄存器和配置,接口端点等-usb2.0 Chinese explanation, combining s3c2410 chips, Details of the register and configuration, interface, and other endpoint
- 2022-08-02 19:02:49下载
- 积分:1
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本软件是图象处理软件,能对图象进行简单的处理,如中值滤波、二值化变换、亮度增减、傅立叶变换、反色、取对数等...
本软件是图象处理软件,能对图象进行简单的处理,如中值滤波、二值化变换、亮度增减、傅立叶变换、反色、取对数等-software is the image processing software, the images can be simple, such as the filter, two values of transformation, Brightness changes, Fourier transform, anti-Israel, and so on, from right
- 2023-04-29 18:35:03下载
- 积分:1
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背包问题动态规划算法JAVA
给定n种物品和一背包。物品i的重量是wi,其价值为vi,背包的容量为c。问应如何选择装入背包中的物品,使得装入背包中物品的总价...
背包问题动态规划算法JAVA
给定n种物品和一背包。物品i的重量是wi,其价值为vi,背包的容量为c。问应如何选择装入背包中的物品,使得装入背包中物品的总价值最大?
在选择装入背包的物品时,对每种物品i只有两种选择,即装入背包或不装入背包。不能将物品i装入背包多次,也不能只装入部分的物品i。因此,该问题称为0-1背包问题。-Knapsack problem dynamic programming algorithm for a given n species JAVA goods and one backpack. Item i is the weight of wi, the value for vi, knapsack capacity c. Question should be how to choose the items into the backpack, the backpack into the total value of the largest items? In the selection of the items into the backpack, for each of the items i have only two choices, that is loaded or not loaded backpack backpack. Items should not be many times i load backpack can not only part of the goods loaded i. Therefore, the problem known as the 0-1 knapsack problem.
- 2023-04-22 23:20:03下载
- 积分:1