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rtw2
基于simulink/RTW的闭环控制系统平台设计(Based on simulink/RTW of the closed-loop control system design of the platform)
- 2007-09-01 15:32:48下载
- 积分:1
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Newton_Bisection
数值计算中的二分法和牛顿迭代法的演示,通过对数值的计算(Numerical calculation of the dichotomy and the Newton iteration of the demonstration, through numerical calculation)
- 2009-03-14 09:43:52下载
- 积分:1
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LDA2
说明: LDA的matlab程序,简单易用,速度快。比其他LDA方法好(Matlab source code for LDA. Fast, and easy to use. Better than other LDA source codes)
- 2011-03-24 12:57:30下载
- 积分:1
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Find-peaks-on-ECG-using-threshold-
Digital signal processing, Find peaks on ECG using threshold
- 2011-05-21 00:56:32下载
- 积分:1
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Machine-learning
多帧图像超分辨率重建,通过机器学习来实现,效果不错。(Multi-frame image super-resolution reconstruction, through machine learning to achieve good results.)
- 2013-11-11 19:11:59下载
- 积分:1
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SVM
对于胡良谋的书《支持向量机故障诊断及控制技术》中的各个例程,绝对有用(For Liang- Mou s book " support vector machine fault diagnosis and control technology" of the various routines)
- 2014-01-14 09:58:58下载
- 积分:1
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Document
code for the protocol of stop and wait
- 2009-12-07 15:59:54下载
- 积分:1
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--Engineering---(ebook---PDF)---Matlab-Programmin
Matlab programming book
- 2012-01-05 04:55:30下载
- 积分:1
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pi
说明: 一个用于求圆周率pi的matlab算法。题目背景:取一长面积为1平方米的正方形白纸,在白纸的内部画一个直径为1米的圆,如下图所示。此圆恰好与正方形的四条边分别切于一点,它的面积是
pi*(1/2)^2 =pi/4 ,然后,你可以抓一大把芝麻,一粒一粒地随便地扔到白纸上。在你扔麦子的过程中可以请一位朋友帮助记录:一共扔了几次?有几次是扔在圆里面?
实验结束后,你只须用“芝麻落在圆里的次数”除以“一共扔的次数”得到的结果就是圆的面积。则pi就是“圆的面积*4”了
当然,你扔的次数越多,结果就越精确!()
- 2007-10-19 21:53:53下载
- 积分:1
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s_stcOCML2GNS
说明: Matlab里计算高维时空混沌OCML的源程序(Matlab to calculate high-dimensional space-time source of chaos OCML)
- 2006-03-30 09:16:46下载
- 积分:1