登录
首页 » matlab » Affine

Affine

于 2010-11-01 发布 文件大小:6KB
0 245
下载积分: 1 下载次数: 227

代码说明:

  Matlab编写的仿射变换程序,有两个,都不错(Affine transformation program written in Matlab, there are two, are good)

下载说明:请别用迅雷下载,失败请重下,重下不扣分!

发表评论

0 个回复

  • cycle_test_algrithm
    lDPC校验矩阵的环检测。包括4环检测算法,6环检测算法及8环检测算法。还包括一个准循环LDPC奇偶校验矩阵的生成算法。(this algrithm can search cycles in LDPC parity check matrix。It contain cycle-4 cycle-6 cycle-8 test algrithm.It also contains a algrithm for generate the LDPC quasi-cyclic parity check matrix )
    2010-03-11 13:46:50下载
    积分:1
  • 11
    说明:  编程序调用MATLAB滤波器设计函数ellipord和ellip分别设计这三个椭圆滤波器,并绘图显示其损耗函数曲线。  (Programmed call MATLAB filter design function ellipord and ellip three elliptic filters were designed, and the drawing shows the loss function curve. )
    2011-05-24 09:12:07下载
    积分:1
  • fortbox
    源代码,是malab中的一个基础的源代码,供大家学习。(Source code, is the malab a basis source code for everyone to learn.)
    2012-07-13 04:07:31下载
    积分:1
  • voltage_profile
    calculate voltage profile for power systems in matlab M-file
    2013-09-08 15:27:04下载
    积分:1
  • VCPP-and-MATLAB
    VC++与MATLAB混合编程研究及开发实例(VC++ and MATLAB)
    2011-12-17 16:28:47下载
    积分:1
  • svpwmsl
    异步电机的SVPWM矢量控制,转速恒定,MATLAB版本2013。(The SVPWM vector control of asynchronous motor, a constant speed, MATLAB version 2013.)
    2015-05-01 14:24:58下载
    积分:1
  • emd
    可以进行经验模式分解的matlabd源程序(Empirical mode decomposition can be the source matlabd)
    2009-02-24 17:05:47下载
    积分:1
  • Shape-Recognition
    這是一個可以自動尋找图像中的長方形, 正方形, 圓形, 菱形的程式(1- Read the RGB (colored) image in from user. 2- Convert image from (RGB) colored to gray image. 3- Threshold the image (convert gray image to binary image). 4- Invert the binary image (in order to speed up the time of processing). 5- Find the boundaries concentrate. 6- Determine shapes properties (ratio of dimensions, roundness). 7- Classify shapes according to its properties. )
    2009-04-11 14:58:22下载
    积分:1
  • shighpassf
    高通系统源程序,简单的例子,主要对于初学者。( High passes the system source program, simple example, mainly regarding beginner. )
    2006-07-13 23:12:38下载
    积分:1
  • newton
    用牛顿迭代法求方程 f(x)=x³ -x² -1=0 在x。=1.5附近的一个实根。取§=0.000001,取最大迭代数为60. (With Newton iteration equation for f (x) = x ³-x ² -1 = 0 in x. = 1.5 near the root of a real. Take § = 0.000001, take the largest number of 60 iterations.)
    2009-06-20 22:57:57下载
    积分:1
  • 696516资源总数
  • 106554会员总数
  • 12今日下载