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Matlab
有关Matlab的一些关于计算性问题的源程序代码，做课程设计时用到的,有一定的实用价值
(For Matlab source code on computational problems, to do curriculum design used.)
- 2012-06-06 21:56:45下载
- 积分：1
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sharpMapTEST
源码sharpMap分析，所有sharpMap开发文档整理，适合初级开发者和有一定sharpMap开发基础(Source sharpMap analysis, all the sharpMap Development Documentation finishing, suitable for junior developers and have a certain sharpMap Development Foundation)
- 2010-03-01 17:35:49下载
- 积分：1
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w_ipp-sample-jpeg_p_5.0.010
intel的ipp性能库sample code，提供了加速的静态图象处理示例，充分显示了ipp在多核平台下的性能优势(intel performance of ipp library sample code, provided the acceleration of static image processing example, it shows that in multi-core platform ipp performance advantages)
- 2007-08-29 11:12:54下载
- 积分：1
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2014
2014 Continuous Learning of Human Activity Models - imp(2014 Continuous Learning of Human Activity Models- imp)
- 2015-03-15 19:10:40下载
- 积分：1
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smarttoalive
15名基督教徒和15名异教徒同乘一船航行，途中风浪大作，危机万分，领航者告诉大家，只要将全船的一半人投入海中，其余人就能幸免。大家都同意这个办法，并协定者30人围成一圈；由第一个人起报数，每数至第9人便把他投入海中，下一个接着从1开始报数，第9人又被投入海中，依次循环，直至剩下15人为止。问题是如何排法使投入海中的人全为异教徒？(15 Christians and pagans 15 vessels with one by the way, big waves, extreme crisis, leader told everyone that as long as will be half the person boat into the sea, and the remaining person will be able to escape. We all agree that this approach, and agreements were 30 form a circle from the first reported from a few individuals, the number to 9 for each person put him into the sea, then from the next one to start off, 9 people have been invested in the sea, followed by cycle, until the remaining 15 people so far. The question is how to row Act so that the person into the sea all infidels?)
- 2009-02-21 17:02:08下载
- 积分：1
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7
说明： matlab高效编程程序源代码第七章，可以运行。(efficient programming source code matlab Chapter VII, to run.)
- 2011-04-10 15:34:15下载
- 积分：1
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Doppler-radar-driver
多普勒雷达驱动程序，应用于室内导航与定位(Doppler radar driver)
- 2015-04-02 11:56:05下载
- 积分：1
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Professional-Image-Modifier-3
Image setter windows phone 8
- 2015-02-08 08:14:38下载
- 积分：1
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read
用matlab实现的视频读取并提取目标背景，对初学者很有用(failed to translate)
- 2009-05-10 15:36:51下载
- 积分：1
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MA4
串的一些基本运算，删除一段子串，置换，求s串中从start位置开始长度为len的子串等等(Some of the basic string operations, delete a substring, replacement, seeking s string starting from the start position of the sub-string of length len, etc.)
- 2009-11-16 13:10:13下载
- 积分：1
