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yuanma
说明： 计算线性规划问题，以及简单的优化问题解决方案，matlab主要用于数学计算方面，是很简单的数学软件(Calculation of linear programming problems, and simple solutions for optimization problems, matlab mainly for mathematical calculations, is a very simple mathematical software)
- 2009-04-12 16:06:10下载
- 积分：1
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Untitled
松弛算法：预报误差法参数辨识。刘辉，系统辨识(Untitled)
- 2021-03-31 14:59:09下载
- 积分：1
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niudunxiange
MATLAB中利用牛顿法弦割法对多项式进行求解的源代码(MATLAB, chord cutting method using Newton method for solving polynomial source code)
- 2014-12-01 14:07:31下载
- 积分：1
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Artificial-neural-networks
压缩文件中有两个文件，其中一个是基于BP、RBF人工神经网络解决变压器故障诊断的问题。另外一个文件是用进退法、黄金分割法、DFP、Powell的方法解决函数最小值。(
There are two archive files, one of which is based BP, RBF artificial neural network to solve the problem of transformer fault diagnosis. Another document is the solution to function with the minimum of advance and retreat method, golden section method, DFP, Powell method.)
- 2016-02-15 17:37:54下载
- 积分：1
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ML1
here data is given and estimate using ML estimation in pattern recognition
- 2013-04-02 19:58:47下载
- 积分：1
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RScode
RS编码的例子，可以参考这个学RS编码,可以参考通信原理的书籍来对照来学！(This is a example about RS coding ,and you can learn RS by that.)
- 2010-08-01 20:59:56下载
- 积分：1
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36.815
LTE--A最新标准815系列，对于研究LTE-A系统非常有用(LTE- A New Standard 815 series, for the study of LTE-A system is useful)
- 2010-05-09 12:19:26下载
- 积分：1
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xbresson_2009_NLTV
compressive sensing theory
- 2013-08-16 22:11:28下载
- 积分：1
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fir
用matlab设计FIR维纳滤波器
假设一个点目标在x，y平面上绕单位圆做圆周运动，由于外界干扰，其运动轨迹发生了偏移。其中，x方向的干扰为均值为0，方差为0.05的高斯噪声；y方向干扰为均值为0，方差为0.06的高斯噪声。用该滤波器处理观测信号，得到其最佳估计。(FIR Wiener filter design using matlab
Suppose a point target in the x, y plane around the unit circle in a circular motion due to external interference, its trajectory shift occurred. Which, x the direction of the interference of mean 0 and variance of 0.05 Gaussian noise y direction of the disturbance is zero mean Gaussian noise variance 0.06. Observed with the filter processing signal, to get the best estimate.)
- 2011-12-14 16:24:52下载
- 积分：1
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chapter2
Power Systems Oscillations C2 examples
- 2013-01-05 10:00:38下载
- 积分：1
