登录
首页 » Visual C++ » time-clock

time-clock

于 2011-10-05 发布 文件大小:1KB
0 188
下载积分: 1 下载次数: 4

代码说明:

  本段程序是介绍关于如何实现数字秒表的程序(This section of the program is to introduce the digital stopwatch on how to program)

下载说明:请别用迅雷下载,失败请重下,重下不扣分!

发表评论

0 个回复

  • vc2004
    此 CHM 文档的内容均为 CSDN 众网友共同收集而来,由网友们于 2004 年 3 月 7 日在 www.csdn.net 网站 VC/MFC 版的非技术类论坛上正式提出整理工作的倡议,经王国凡同志(sgnaw 李逍遥)整理而成,以供大家工作学习参考之用。 我自认为是一个比较热心的人,经常帮助同学同事们解决 IT 方面的问题,有时也逛逛 CSDN。我在武汉出身,也在武汉工作三年了,希望将来能为 IT 业的发展作出贡献。整理工作虽然辛苦,但也快乐,错漏之处再所难免,如有建议或意见请联系 sgnaw@163.com(CHM contents of this document are the common netizen CSDN collected from the public, from users in March 7, 2004 in www.csdn.net site VC/MFC version of the non-technical categories of the official presentation of the Forum on the initiative of finishing the work by Where the Kingdom of Comrade (sgnaw Li Xiaoyao) collated from for everyone to learn the work of reference. Since I think is a more enthusiastic, often to help students solve IT colleagues issues, and sometimes go CSDN. I am born in Wuhan, Wuhan is also working for three years and hopefully in the future for the IT industry to contribute to the development. While finishing work hard, but also happy, errors and omissions are inevitable and then, if the recommendations or comments please contact sgnaw@163.com)
    2008-07-16 17:52:14下载
    积分:1
  • C
    说明:  c语言程序设计———————谭浩强第三版(c)
    2010-12-01 13:41:34下载
    积分:1
  • Modtran3.7
    大气透过率计算软件,1997年Motran3.7版本,分辨率更高(Motran3.7)
    2010-09-03 12:26:00下载
    积分:1
  • videocompressionpaper
    本论文首先系统地介绍了视频压缩编码的基本原理和方法,以及各国际标准 化组织提出的压缩标准;其次分析了JPEG和MPEG-4的主要技术,据此提出 MPEG-4简单框架编码器的软件实现方案,给出流程图,在VC++环境下用C语言 程序实现了JPEG压缩及MPEG-4简单框架的视频压缩功能,采用测试序列验证 无误,并对两种标准的压缩比进行试验对比,突出压缩的关键技术为DCT和运动 估计算法;接着深入研究了DCT变换、运动估计和补偿算法并进行了优化改进, 给出了用于快速匹配块的自适应十字模式搜索算法,并给出了对各种块匹配估计 算法的仿真结果。然后详细介绍了TI公司TMS320C6711DSP的软硬件特性,并 在此基础上提出系统的硬件实现方案。接着介绍了基于系统软硬件环境的移植问 题和优化方法,并针对算法移植和仿真过程中的问题进行了说明。 最后就课题设计过程中研究的结果予以总结,并阐述了以后课题研究的要点。(In this thesis,an introduction to video compression principal,methods and central international video coding standards is done firstly.Then analyzing the core techniques of JPEG and MPEG-4 and proposing a scheme of MPEG-4 SP encoder,the coding function of JPEG and MPEG-4 is achieved in C successfully with test sequence Then compare the compressed ratio of two standards,point out the key of compression is DCT and Motion Estimation algorithm.Afterwards,studying the DCT/Motion Estimation/Motion Compensation algorithm in detail and giving an adaptive rood pattern search for fast Block-Matching motion estimation.Then the simulation of several motion estimation algorithms based block-matching is given.Accordingly,a scheme of a DSP-based video compression system is put forward,with the features of TI’s TMS320C6711 DSP.At last,the transplant and optimization are considered on the basis of soft and hard environments,also the simulation process. In the end,the summarization about the)
    2009-09-18 10:40:44下载
    积分:1
  • T-REC-X.683-200811-I!!PDF-E
    Abstract Syntax Notation One (ASN.1): Parameterization of ASN.1 pecifications ASN.1 参数化规范(Abstract Syntax Notation One (ASN.1): Parameterization of ASN.1 pecifications )
    2012-04-13 15:21:09下载
    积分:1
  • MFC
    深入浅出MFC第二版,候俊杰著,适合深入研究的开发人员,不建议初学者(MFC easy, second edition, Hou Junjie book, suitable for in-depth study of the developer is not recommended for beginners)
    2013-04-27 19:26:56下载
    积分:1
  • CPP-classic-code-Daquan
    C++经典代码大全,很好的一本资料,希望大家会喜欢(C++ classic code Guinness, a good information, I hope you will like)
    2014-02-22 19:02:05下载
    积分:1
  • RGBsensor
    说明:  一种rgb传感器的技术手册的和介绍,包括使用方法和详细资料(A rgb sensor and introduction of technical manuals, including the use of methods and details)
    2011-03-13 22:01:11下载
    积分:1
  • 02-Qt-Designer-application
    Qt Designer应用东软培训资料,对初学者很有用。这是第二部分。(Qt Designer application Neusoft training materials, useful for beginners. This is the second part.)
    2013-07-29 09:14:21下载
    积分:1
  • surprising-munbers
    C语言实现 一个自然数的七进制表达式是一个三位数,而这个自然数的九进制表示也是一个三位数,且这两个三位数的数码顺序正好相反,求这个三位数。(C language a natural number is a seven-digit hexadecimal expression, and this natural number is a nine-digit hexadecimal representation, and the two-digit digital opposite order, find the three digits.)
    2013-05-25 22:44:49下载
    积分:1
  • 696516资源总数
  • 106409会员总数
  • 8今日下载