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单片机控制步进驱动,S1为启动,S2为停止,S3为加一,S4为减一...
单片机控制步进驱动,S1为启动,S2为停止,S3为加一,S4为减一-Single-chip stepper drive control, S1 for the launch, S2 to stop, S3 for the plus-one, S4 for by one
- 2022-03-04 16:58:57下载
- 积分:1
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24C02的读写操作,用汇编语言完成,在开发板上运行正常
24C02的读写操作,用汇编语言完成,在开发板上运行正常-24C02
- 2022-06-17 12:26:49下载
- 积分:1
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M16内部采样并用Max7221
M16内部采样并用Max7221-7219显示-M16 and the internal sampling showed Max7221-7219
- 2022-10-17 21:45:03下载
- 积分:1
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pid控制例程,演示一钟摆运行情况,可方便移植到其它应用
pid控制例程,演示一钟摆运行情况,可方便移植到其它应用-pid control routines, a demonstration run of the pendulum may be convenient to other applications transplant
- 2022-03-02 21:53:57下载
- 积分:1
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可用于单片机的方法同程序,尚未通过验证,大家慎用,也许不错...
可用于单片机的方法同程序,尚未通过验证,大家慎用,也许不错-Single-chip method can be used with the procedure, has not yet been validated, we used with caution, and perhaps a good
- 2022-12-10 00:35:03下载
- 积分:1
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该源代码是用于串口通讯的,本着资源共享的精神,发
该源代码是用于串口通讯的,本着资源共享的精神,发-The source code is used for serial communications, in line with the spirit of sharing resources, the
- 2022-11-19 08:10:03下载
- 积分:1
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这是一个51系列单片机控制加热温度的程序,使用了pid算法。
这是一个51系列单片机控制加热温度的程序,使用了pid算法。-This is a 51 series single-chip microcomputer to control the heating temperature of the procedures, the use of pid algorithm.
- 2023-07-20 05:15:04下载
- 积分:1
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根据输入的年,月,日 计算出星期几。
单片机数码管显示和键盘输入,...
根据输入的年,月,日 计算出星期几。
单片机数码管显示和键盘输入,-Based on the input of the year, month, day, calculate the day of the week. Microcontroller digital tube display and keyboard input,
- 2022-02-12 14:22:23下载
- 积分:1
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三
三相步进电机的三相六拍工作方式,正转的绕组通电顺序:A、AB、B、BC、C、CA、A,反转的通电顺序:A、AC、C、CB、B、BA、B、A。
由于步进电机转子有一定的惯性以及所带负载的惯性,故步进电机的工作过程中不能及时的启动和停止,在启动时应慢慢的加速到预定速度,在停止前应逐渐减速到停止,否则,将产生失步现象。
步进电机的控制问题可总结为两点:
1、产生工作方式需要的时序脉冲;
2、控制步进电机的速度,使它始终遵循加速、匀速、减速的规律工作。
-Three-phase three-phase stepper motor six shot work, is to order the winding power: A, AB, B, BC, C, CA, A, reverse the order of power: A, AC, C, CB, B, BA, B, A. As the stepper motor rotor has a certain degree of inertia, as well as brought about by the inertia load, the stepper motor during the course of work should not start and stop time, start to be slowly accelerated to a predetermined speed, the stop should be to slow down gradually to the stop, otherwise, will result in out-of-step phenomenon. Stepper motor control problems can be summarized in two points: one, resulting in the need to work the timing pulse 2, control the speed of stepper motor, so that it always followed acceleration, velocity, deceleration of the law of the work.
- 2022-07-20 15:21:46下载
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这是用vhdl语言写8051单片机的文档和程序.
这是用vhdl语言写8051单片机的文档和程序.-vhdl This is the language used to write 8051"s files and procedures.
- 2023-08-18 13:20:04下载
- 积分:1