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c language algorithm. . . . Can be useful for the examination can be used to be
c语言算法 。。。。可以对考试很有用
可以用来被-c language algorithm. . . . Can be useful for the examination can be used to be
- 2022-02-21 13:52:55下载
- 积分：1
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相关的语音处理，适合于现代数字信号处理的课程设计，，，并且可以运行...
相关的语音处理，适合于现代数字信号处理的课程设计，，，并且可以运行-related to the speech processing, which is suitable for modern digital signal processing design of, and can run
- 2023-02-26 01:55:03下载
- 积分：1
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这是拉格朗日插值的源码
这是拉格朗日插值的源码-This is the source Lagrange interpolation
- 2022-02-10 05:58:03下载
- 积分：1
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IMBE解码库
IMBE decoding library.rar
详细说明：IMBE解码库，可解IMBE3600,7200两种码率，适用于P.25,MOTOROLA的DMR-IMBE decoding library,
solvable IMBE3600, 7200 two kinds of bit rate, for P.25, MOTOROLA s DMR
文件列表:
文件夹：IMBE decoding library
mbelib-1.2.3ambe3600x2250.c
............ambe3600x2250_const.h
............CHANGELOG
............config.h
............configure
............COPYRIGHT
............ecc.c
............ecc_const.h
............imbe7100x4400.c
............imbe7200x4400.c
............imbe7200x4400_const.h
............Makefile
............mbelib.c
............mbelib.h
............mbelib_Author.pgp
............mbelib_const.h
PATENT NOTICE
&nb
- 2022-02-12 01:06:20下载
- 积分：1
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一个正二十面体的细分迭代工程,很漂亮,需要glut
一个正二十面体的细分迭代工程,很漂亮,需要glut-an icosahedron is the breakdown of iterative engineering, and very pretty, needs glut
- 2022-07-12 14:02:38下载
- 积分：1
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下相当的问题说明：2个可装2个八个玻璃…
倒酒问题描述： 设有两个能装8两的酒杯（称为１号，２号）装满了酒, 和1个能装3两的空酒杯（称为３号）, 问怎样用这3个酒杯向4个人 敬酒, 使得每个人都喝4两酒. 要求： 用程序计算出可行方案。 输入： 无 输出： 每一步决策．-down quite Problem description : two can be loaded with two of the eight glasses (known as 1, 2) filled with the wine, and one can hold three two empty glasses (known as the 3rd) and asked how to use it three to four glasses and toast the individual, so that each person maximum servings of both types 4 2 liquor. Request : procedures calculated options. Input : None output : each step of the decision-making.
- 2023-06-15 16:35:03下载
- 积分：1
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该程序用递归的方法产生格雷码序列,它需要一定的额外的空间....
该程序用递归的方法产生格雷码序列,它需要一定的额外的空间.-the procedures used recursive methods Gray code sequence, it needs the additional space.
- 2022-04-11 15:53:22下载
- 积分：1
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素数环： 把从1到10这10个数摆成一个环，要求相邻的两个数的和是一个素数。 〖问题分析〗 这是一道回溯的题目。从1开始，每个空位有9种可能，每种可能加入约束...
素数环： 把从1到10这10个数摆成一个环，要求相邻的两个数的和是一个素数。 〖问题分析〗 这是一道回溯的题目。从1开始，每个空位有9种可能，每种可能加入约束条件即可
1.与前面所有的数不重复
2.与前一个数和为素数（最后一个和第一个也要满足）。 〖算法流程〗 1、数据初始化； 2、递归填数： 判断第J种可能是否合法； A、如果合法：填数；判断是否到达目标（10个已填完）： 是，打印结果；不是，递归填下一个； B、如果不合法：选择下一种可能；-Prime Central: 1-10 from 10 the number of put this into a ring, asked the two adjacent numbers and is a prime number. 〗 〖Analysis is a retrospective this topic. From 1 year, 9 out of every space possible, each may be bound by the conditions of accession to 1. And in front of all the number of non-repetition, 2. With a few and for a prime number (the last and the first to meet). 1〗 〖algorithm processes the data to initialize 2, fill in the number of recursion: first to determine the legality of J possible A, if the legitimate: the number of Reclamation to determine whether the target (10 have been completed): Yes, print the results of not, fill in the next recursive B, if not legitimate: a possible alternative
- 2022-03-13 12:39:07下载
- 积分：1
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Least Soft-thresold Squares Tracking
we propose a generative tracking method based on a novel robust linear regression algorithm. In con-
trast to existing methods, the proposed Least Soft-thresold Squares (LSS) algorithm models the error term with the
Gaussian-Laplacian distribution, which can be solved ef- ficiently. Based on maximum joint likelihood of parameters,
we derive a LSS distance to measure the difference between an observation sample and the dictionary. Compared with
the distance derived from ordinary least squares methods, the proposed metric is more effective
- 2022-03-22 17:30:20下载
- 积分：1
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is on the duality transformation
是关于对偶变换的-is on the duality transformation
- 2022-06-01 06:37:25下载
- 积分：1
