-
M_M
此为数学形态滤波器消燥的代码，用于一维信号，涉及一个具体的例子，需要的话可以自己修改，修改相应的结构元素。(This is a mathematical morphology filter away dry code, used to one dimensional signal, involving a concrete example, necessary can change ourselves, change the structure of the corresponding elements)
- 2013-08-29 21:36:37下载
- 积分：1
-
vend
自动售货机，根据所要的东西，自动收费，并进行找零(Vending machine, according to what you want to automatically charge and conduct Keep the change)
- 2010-01-10 16:56:54下载
- 积分：1
-
verilog程序设计教程，适合初学者。
verilog程序设计教程，适合初学者。-verilog programming tutorial for beginners.
- 2023-03-06 05:00:04下载
- 积分：1
-
32_lvds_test
说明： Xilinx 公司Spartan-6系列FPGA实现LVDS，带Modelsim仿真文件，已综合。(Xilinx Spartan-6 Series FPGA implements LVDS with Modelsim simulation file, which has been synthesized.)
- 2020-11-30 20:59:27下载
- 积分：1
-
SDRAM 控制器与仲裁者
SDRAM 控制器的多 CPU 系统的公断人将调度内存访问。
- 2023-07-15 19:45:03下载
- 积分：1
-
sim_uart
uart 收发器 verilog 代码，实现自收发功能
sys clk = 25m, baud 9600 停止位1， 无校验位；
代码实现了串口自收发功能，及把从 PC 收到的内容都发送会 PC, 其他波特率，自行修改代码即可，在 alter 的FPGA 上调试通过；
(verilog code uart transceiver to achieve self-transceiver function sys clk = 25m, baud 9600 1 stop bit, no parity code from the transceiver features a serial port, and the contents received from the PC will send the PC, another Potter rate, self-modifying code can, in the alter of the FPGA, debugging through )
- 2010-10-10 21:49:46下载
- 积分：1
-
cordic
verilog编写的数字信号发生器NCO用CORDIC方法实现产生sin cos信号，流水线结构，简单实用。(verilog prepared by the digital signal generator NCO using CORDIC method implementation generate sin cos signal, pipelined architecture, simple and practical。)
- 2021-04-09 11:38:59下载
- 积分：1
-
EMIF
EMIF接口调试代码，使用的是Verilog语言，FPGA与DSP通信，测试成功(EMIF interface debugging code that USES the Verilog language, FPGA and DSP communication, testing success)
- 2020-12-04 10:39:24下载
- 积分：1
-
主要介绍了ＦＰＧＡ设计的基本原则、基本设计思想、基本操作技巧、常用模块。...
主要介绍了ＦＰＧＡ设计的基本原则、基本设计思想、基本操作技巧、常用模块。-Mainly introduces the basic principles of FPGA design, basic design concepts, basic operating skills, commonly used modules.
- 2022-08-25 13:03:15下载
- 积分：1
-
ML605板子上的灯
ML605评估板上的流水灯，可以实现每隔0.16秒进行+1操作
#include
#include
#include
#include
#include
int main()
{
char a[] = "-100" ;
char b[] = "123" ;
int c ;
c = atoi( a ) + atoi( b ) ;
printf("c = %d
", c) ;
return 0;
- 2022-06-01 23:28:16下载
- 积分：1
