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完成PWM控制采用VHDL语言，你可以看看它。
done pwm control using vhdl ,you can look at it.
- 2022-02-06 06:14:03下载
- 积分：1
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这是一个简单的除法器（32bit/16bit),采用移位相减法
这是一个简单的除法器（32bit/16bit),采用移位相减法-This is a simple divider (32bit/16bit), using phase shift subtraction
- 2022-07-06 17:00:38下载
- 积分：1
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pn sequence generator
本设计是一个伪随机数发生器。此设计；
- 2023-02-23 15:45:04下载
- 积分：1
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USERMANUL
LPC4357开发板采用ARM的Cortex-M4微控制器LPC4357。内置一个ARM Cortex-M0协处理，CPU运行频率高达204MHz，片内集成1MB Flash和36KB SRAM。开发板采用独立核心板设计，核心板集成64MB SDRAM、128MB NAND-Flash、4MB SPI-Flash。核心板上的摄像头接口可直接连接各种型号的摄像头，两侧160P排针接口引出了除EMC总线外的LPC4357芯片所有功能管脚。
开发板提供丰富的外设接口，包括以太网、液晶屏、摄像头、USB-Host、USB-OTG、SD卡、RS232、RS485、CAN、耳机、麦克风、温度传感器、AD/DA、JTAG仿真器等。此外，开发板提供一个14P扩展接口，包括1路UART、1路SPI、1路I2C、4个IO、3.3V、5V，可以很方便的扩展自己的外围电路。(DS-LPC4357 development board using the Cortex-M4 microcontroller LPC4357 ARM s. A built-in ARM Cortex-M0 co-processor, CPU operating frequency up to 204MHz, 1MB Flash and 136KB SRAM integrated on chip.
Development board using an independent core board design, the core board integrates 64MB SDRAM, 128MB NAND-Flash, 4MB SPI-Flash. Camera core board interface can be directly connected to various types of cameras, both sides 160P pin interface leads to the outside of the bus in addition to EMC LPC4357 chip all the functions of the pins.
Development board provides a rich set of peripheral interfaces, including Ethernet, LCD screen, camera, USB-Host, USB-OTG, SD card, RS232, RS485, CAN, headphone, microphone, temperature sensor, AD/DA, JTAG emulator, etc. . In addition, the development board provides a 14P expansion interfaces, including one-way UART, 1 road SPI, 1 channel I2C, 4 个 IO, 3.3V, 5V, can easily expand their peripheral circuits.)
- 2016-02-23 16:58:53下载
- 积分：1
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UART_DMA
UART_DMA的方法是使用nios实现UART方式实现DMA传输，在硬件平台上通过验证实现(UART_DMA way is to use uart dma transfer nios implemented in the hardware platform validated by)
- 2020-11-03 10:39:53下载
- 积分：1
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VerilogHDL.自动增益控制模块中产生控制电压的部分
VerilogHDL.自动增益控制模块中产生控制电压的部分-VerilogHDL. Automatic Gain Control Module have some control voltage
- 2022-06-19 20:17:38下载
- 积分：1
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This is an FPGA
这个是一个基于FPGA的SDRAM控制器系统，实现对SDRAM的读写操作，用来实现时序的控制-This is an FPGA-based SDRAM controller system, the read and write operations to SDRAM to achieve the control of timing
- 2022-02-02 20:49:24下载
- 积分：1
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Dec_mul
时间同步后即可确定每帧数据的起始位置，这样就能完整的截取下每一帧。但是，数据中还带有频偏信息。在常规的通信系统中，多普勒很小仅仅会带来很小的频偏，但是在大多普勒的情况下，频偏将非常大，20马赫的速度将会带来将近34K的频偏。因此，如何很好的纠正频偏即为本系统的难点。
OFDM中，我们将大于子载波间隔倍数的频偏称为整数倍频偏，而将小于一个子载波间隔的频偏称为小数倍频偏。频偏矫正精度只要能保证小于十分之一倍的子载波间隔，频偏就不会对均衡和解调造成影响。本文中我们借鉴这种思想，由于硬件资源限制，我们将在接收端做64点FFT，即相当于将频域划分为64份，我们将小于 的频偏称为小数倍频偏，将 整数倍的频偏称为整数倍频偏。本程序即基于SCHIMDL经典方法完成小数倍频偏纠正(After time synchronization can determine the starting position of each frame data, so you can complete the interception of each frame. However, in the data with frequency information. In conventional communication systems, doppler small will bring only small deviation, but in the case of most of the doppler, frequency PianJiang is very large, 20 Mach speed will lead to deviation of nearly 34 k. Therefore, how to good to correct deviation is the difficulty of this system.
OFDM, we will be bigger than the sub-carrier spacing ratio of frequency deviation is called the integer frequency offset, and the interval will be less than a child carrier frequency offset is called decimal frequency doubling. Deviation is less than one over ten times as long as can guarantee accuracy of sub-carrier spacing, deviation will not affect balance and demodulation. This article, we draw lessons from the idea, due to the limited hardware resources, we will do 64 points FFT at the receiving end, which is equ)
- 2013-12-26 18:00:24下载
- 积分：1
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Modulation
产生长度为100的随机二进制序列
发送载波频率为10倍比特率，画出过采样率为100倍符号率的BPSK调制波形（前10个比特） ，及其功率谱
相干解调时假设收发频率相位相同，画出x(t) 的波形，假设低通滤波器的冲激响应为连续10个1（其余为0），或连续12个1 （其余为0） ，分别画出两种滤波器下的y(t)，及判决输出（前10个比特）
接收载波频率为10.05倍比特率，初相位相同，画出x(t) 的波形，假设低通滤波器的冲激响应为连续10个1，画出两种滤波器下的y(t)，及判决输出（前20个比特）
采用DPSK及延时差分相干解调，载波频率为10倍比特率，画出a, b, c, d点的波形（前10个比特）
DPSK及延时差分相干解调，载波频率为10.25倍比特率时，画出a, b, c, d点的波形（前10个比特）
DPSK及延时差分相干解调，载波频率为10.5倍比特率时，画出a, b, c, d点的波形（前10个比特）
(Produce random binary sequence of length 100
The transmission carrier frequency is 10 times the bit rate, draw a sampling rate of 100 times the symbol rate of the BPSK modulation waveform (first 10 bits), its power spectrum
Coherent demodulation of assuming the same as the phase of the transmitting and receiving frequencies, and draw the waveform x (t), assuming that the impulse response of the low pass filter 10 consecutive 1 (the remainder is 0), or 12 consecutive 1 (the remainder is 0), y (t) is drawn under the two filters respectively, and the decision output (10 bits)
The received carrier frequency is 10.05 times the bit rate, the same initial phase, draw the waveform x (t), assuming that the impulse response of the low pass filter of 10 consecutive 1, shown under two filter y (t), and decision output (20 bits)
DPSK and delay differential coherent demodulation, the carrier frequency is 10 times the bit rate, draw a, b, c, d point of the waveform (first 10 bits)
DPSK and delay)
- 2020-12-14 08:19:14下载
- 积分：1
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PID_Verilog
说明： 之前一直找不到自学编写了一个，PID案例，分享下(I have been unable to find a self-taught, compiled a PID case, share under)
- 2020-10-08 13:26:54下载
- 积分：1
